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3 years ago

5

Find the length of AB. АE:14 AD:12 AB: BC:18

1 answer:

Afina-wow [57]3 years ago

7 0

Answer:

Whre is the question I don't get it

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What is the volume of a cylinder tank with diameter of 50cm and height of 80cm

stepladder [879]

Answer:

12566.37061435917

or

4000π

Step-by-step explanation:

the equation is 50π×80

this is because you have to find the area of the circle which is diameter times pi and then you multiply that by the height of the cylinder

5 0

3 years ago

What is .333 written in its simplest fraction from

gayaneshka [121]

Hi.
your answer is 1/3, or 2/6, or 3/9, or 4/12, etc.
hope this helps!!!

6 0

3 years ago

54x^3 +250y^3<br> in the sum of cubes<br> please helpppp

Slav-nsk [51]

Answer:

What is exactly the question?

4 0

3 years ago

Below are survival times (in days) of 13 guinea pigs that were injected with a bacterial infection in a medical study:

tresset_1 [31]

Outliers are data that are relatively far from other data elements.

The dataset has an outlier and the outlier is 120

The dataset is given as:

91 83 84 79 91 93 95 97 97 120 101 105 98

Sort the dataset in ascending order

79 83 84 91 91 93 95 97 97 98 101 105 120

<h3>The lower quartile (Q1)</h3>

The Q1 is then calculated as:

$Q1 = \frac{N +1}{4}th$

So, we have:

$Q1 = \frac{13 +1}{4}th$

$Q1 = \frac{14}{4}th$

$Q1 = 3.5th$

This is the average of the 3rd and the 4th element

$Q1 = \frac{1}{2} \times (84 + 91)$

$Q1 = 87.5$

<h3>The upper quartile (Q3)</h3>

The Q3 is then calculated as:

$Q3 = 3 \times \frac{N +1}{4}th$

So, we have:

$Q3 = 3 \times \frac{13 +1}{4}th$

$Q3 = 3 \times 3.5th$

$Q3 = 10.5th$

This is the average of the 10th and the 11th element.

$Q_3 =\frac12 \times (98 + 101)$

$Q_3 =99.5$

<h3>The interquartile range (IQR)</h3>

The IQR is then calculated as:

$IQR = Q_3 -Q_1$

$IQR = 99.5 - 87.5$

$IQR = 12$

Also, we have:

$IQR(1.5) = 12 \times 1.5$

$IQR(1.5) = 18$

<h3>The outlier range</h3>

The lower and the upper outlier range are calculated as follows:

$Lower = Q_1 - IQR(1.5)$

$Lower = 87.5- 18$

$Lower = 69.5$

$Upper = Q_3 + IQR(1.5)$

$Upper = 99.5 + 18$

$Upper = 117.5$

120 is greater than 117.5.

Hence, the dataset has an outlier and the outlier is 120

Read more about outliers at:

brainly.com/question/9933184

6 0

2 years ago

Find the derivative of f(x) = negative 9 divided by x at x = -8.

marusya05 [52]

Answer:

$f'(-8)=\frac{9}{64}$

Step-by-step explanation:

Given the function

$f(x)=\frac{-9}{x}$

We can rewrite it as

$f(x)=-9x^{-1}$

Now we can apply the power rule

$f'(x)=9x^{-2}$

Now we can rewrite it

$f'(x)=\frac{9}{x^{2} }$

Now we can plug in x=-8

$f'(-8)=\frac{9}{(-8)^{2} }\\f'(-8)=\frac{9}{64}$

7 0

3 years ago