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2 years ago

Find the length of AB. АE:14 AD:12 AB: BC:18

Mathematics

1 answer:

Afina-wow [57]2 years ago

7 0

Answer:

Whre is the question I don't get it

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Solve for r.<br><br> -35= -7r

GalinKa [24]

R= 5
You divide -7 by both sides to 1. Cancel out the -7 2. To simplify the -35. So simplified -35/-7=5

3 0

2 years ago

Given f(x)=-3x+3solve for x when f(x)=6

natali 33 [55]

Answer:

x = -1

Step-by-step explanation:

Given: $f(x) = - 3x + 3$

Solve for x, When: $f(x) = 6$

Step by step:

$- 3x + 3 = 6$

$- 3x = 6 - 3$

$- 3x = 3$

$x = 3 \div - 3$

$\boxed{\green{x = - 1}}$

3 0

2 years ago

Solve: 9x - 3 = 729

Ivahew [28]

Answer:

its . 6

Step-by-step explanation:

e2020

5 0

2 years ago

Read 2 more answers

What is the original price if the discount is 36% and the sale price is $32

Andrei [34K]

The answer is $50
Assume the original cost price to be $x

Therefore ,
X - 36X/100 = $32
-> 100x - 36x = 32 x 100
-> 64x = 3200
-> x = 3200/64
-> x = 50

7 0

2 years ago

Read 2 more answers

Find the general solution of x'1 = 3x1 - x2 + et, x'2 = x1.

Ann [662]

Note that if ${x_2}'=x_1$ , then ${x_2}''={x_1}'$ , and so we can collapse the system of ODEs into a linear ODE:

${x_2}''=3{x_2}'-x_2+e^t$
${x_2}''-3{x_2}'+x_2=e^t$

which is a pretty standard linear ODE with constant coefficients. We have characteristic equation

$r^2-3r+1=\left(r-\dfrac{3+\sqrt5}2\right)\left(r+\dfrac{3+\sqrt5}2\right)=0$

so that the characteristic solution is

${x_2}_C=C_1e^{(3+\sqrt5)/2\,t}+C_2e^{-(3+\sqrt5)/2\,t}$

Now let's suppose the particular solution is ${x_2}_p=ae^t$ . Then

${x_2}_p={{x_2}_p}'={{x_2}_p}''=ae^t$

and so

$ae^t-3ae^t+ae^t=-ae^t=e^t\implies a=-1$

Thus the general solution for $x_2$ is

$x_2=C_1e^{(3+\sqrt5)/2\,t}+C_2e^{-(3+\sqrt5)/2\,t}-e^t$

and you can find the solution $x_1$ by simply differentiating $x_2$ .

7 0

3 years ago