Given:
JK is tangent to a circle with center H
To find:
The length of HK.
Solution:
The image is attached below.
JK = 8 mi, HJ = 15 mi
JK is tangent to a circle.
The tangent is always perpendicular to the radius.
Therefore, m∠J = 90°
Using Pythagoras theorem:
HK² = JK² + HJ²
HK² = 8² + 15²
HK² = 64 + 225
HK² = 289
HK² = 17²
Taking square root on both sides.
HK = 17
The length of HK is 17 mi.
Answer:
-1/2
Step-by-step explanation:
hope this helps!
The weight of an adult lobster i 1lb i hope this helps i personally think it would be (C) 1.14 kg because 1.14 kg is 2.51327 that is the closest weight to an adult lobster
Answer:
EF = 8.8 cm
Step-by-step explanation:
In the given right angled ΔDEF, DE is the hypotenuse while EF and DF are adjacent sides. So that applying the Pythagoras theorem, we have;
=
+ 
=
+ 
=
+ 
262.44 =
+ 184.96
= 262.44 - 184.96
= 77.48
EF = 
= 8.8023
EF = 8.8 cm
The length of side EF is 8.8 cm.
2w + 2l = 354 where w = width and l = length
so we have
2*82 + 2l = 354
2l = 254 - 2*82 = 190
l = 95
length is 95 yards