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valkas [14]
3 years ago
13

Can I get some help on number 23 ? :/

Mathematics
1 answer:
kolbaska11 [484]3 years ago
6 0
We're looking for the volume, since it's trying to find out the cost for filling the entire box.
We have our length, width, and height.
8, 6, and 1.
We're multiplying 8, 6 1, and 0.3 since it is $0.3 per sq ft,
Our equation is:
0.3 (8x6x1) = x
8 x 6 x 1 = 48.
48 x 0.3 is 14.4
$14.4 is your answer
Hope this helps!
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We assume that the data is given by :

x: 30, 30, 30, 50, 50, 50, 70,70, 70,90,90,90

y: 38, 43, 29, 32, 26, 33, 19, 27, 23, 14, 19, 21.

Where X represent the cost for scholarships in thousands of dollars and y represent the cost of life for an academic semester (The data comes from the web)

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m=\frac{S_{xy}}{S_{xx}}

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S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}

S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}

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\sum_{i=1}^n x_i = 30+30+30+50+50+50+70+70+70+90+90+90=720

\sum_{i=1}^n y_i =38+43+29+32+26+33+19+27+23+14+19+21=324

\sum_{i=1}^n x^2_i =30^2+30^2+30^2+50^2+50^2+50^2+70^2+70^2+70^2+90^2+90^2+90^2=49200

\sum_{i=1}^n y^2_i =38^2+43^2+29^2+32^2+26^2+33^2+19^2+27^2+23^2+14^2+19^2+21^2=9540

\sum_{i=1}^n x_i y_i =30*38+30*43+30*29+50*32+50*26+50*33+70*19+70*27+70*23+90*14+90*19+90*21=17540

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S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}=49200-\frac{720^2}{12}=6000

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m=-\frac{1900}{6000}=-0.317

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\bar x= \frac{\sum x_i}{n}=\frac{720}{12}=60

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b=\bar y -m \bar x=27-(-0.317*60)=46.02

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y=-0.317 x +46.02

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