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Studentka2010 [4]
3 years ago
9

Which function is the inverse of f(x) = 2x + 3?

Mathematics
2 answers:
creativ13 [48]3 years ago
4 0

Answer: The answer would be f^-1 (x) = x/2 - 3/2

Allisa [31]3 years ago
4 0

Answer:

y=\frac{x-3}{2}

Step-by-step explanation:

The given function is

f(x)=2x+3

To find the inverse of this function, we have to replace f(x) for y, and then isolate x, as follows

y=2x+3\\y-3=2x\\2x=y-3\\x=\frac{y-3}{2}

Then, we have to switch variables, as follows

y=\frac{x-3}{2}

Therefore, the inverse of the given function is

y=\frac{x-3}{2}

The graph attached shows both functions. The blue line is the inverse of f(x)

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julia-pushkina [17]

Answer:

21

Step-by-step explanation:

4 0
3 years ago
Need help fast!! Need steps also
ruslelena [56]

Answer:

arc AB = 3.14 in

Step-by-step explanation:

circumference of full circle = π2r = (3.14)(2)(6) = 37.68 in

arc AB = (30°/360°)(37.68) = 3.14 in

5 0
3 years ago
Use the Internet to identify a major league ballpark in which the distance from home plate to the center field fence and the hei
Hunter-Best [27]

Answer:

x = 28.60 feet

Step-by-step explanation:

We are given a height of 2 feet above the ground and the angle of elevation of 86 degrees. 

Now, let's assume that the form of our problem is in the form of a right triangle, we can solve for the remaining angle as follows;

180 - (90+86) = 4 degrees

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2/sin 4 = x / sin 86

solving for x we have

x = 28.60 feet

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8 0
3 years ago
Round .1325 to the nearest thousandths
faltersainse [42]
0.133 because 5 mean you have to round up so it is 0.133
3 0
3 years ago
Read 2 more answers
Find the solution of the differential equation dy/dt = ky, k a constant, that satisfies the given conditions. y(0) = 50, y(5) =
irga5000 [103]

Answer:  The required solution is y=50e^{0.1386t}.

Step-by-step explanation:

We are given to solve the following differential equation :

\dfrac{dy}{dt}=ky~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

where k is a constant and the equation satisfies the conditions y(0) = 50, y(5) = 100.

From equation (i), we have

\dfrac{dy}{y}=kdt.

Integrating both sides, we get

\int\dfrac{dy}{y}=\int kdt\\\\\Rightarrow \log y=kt+c~~~~~~[\textup{c is a constant of integration}]\\\\\Rightarrow y=e^{kt+c}\\\\\Rightarrow y=ae^{kt}~~~~[\textup{where }a=e^c\textup{ is another constant}]

Also, the conditions are

y(0)=50\\\\\Rightarrow ae^0=50\\\\\Rightarrow a=50

and

y(5)=100\\\\\Rightarrow 50e^{5k}=100\\\\\Rightarrow e^{5k}=2\\\\\Rightarrow 5k=\log_e2\\\\\Rightarrow 5k=0.6931\\\\\Rightarrow k=0.1386.

Thus, the required solution is y=50e^{0.1386t}.

8 0
3 years ago
Read 2 more answers
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