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Vesna [10]
3 years ago
13

Name a line that is not contained in plane N

Mathematics
2 answers:
Goryan [66]3 years ago
7 0
Line AE as part of the line is protruting out of Plane N. In order for the lines to be considered in of Plane N, the line should not be protruting out.

Hope this helps:)
Lelechka [254]3 years ago
5 0
Line AE.  See how it's drawn with part dashed? The dashed part is to indicate that it's hidden behind the plane, as if the plane were a table top.
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HELP ASAP!!!!!!!!!!
chubhunter [2.5K]

Answer:

7.5

Step-by-step explanation:

\sqrt{0\\.3} = 0.5477225575

Multiply it by 5

= 2.738612788

Square it

7.5 ft^{2}

Hope this helped. :)

5 0
3 years ago
Find the product of (2x − 5y)2
pishuonlain [190]

Answer:

(2x - 5y)²

(2x - 5y)(2x - 5y)

2x(2x - 5y) - 5y(2x - 5y)

2x(2x) - 2x(5y) - 5y(2x) + 5y(5y)

4x² - 10xy - 10xy + 25y²

4x² - 20y + 25y²

The answer is B.

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Deon is riding his bicycle. He rides for 7 hours at a speed of 22.4 kilometers per hour. For how many kilometers does he ride
salantis [7]
By hypothesis, Deon is riding at a speed of 22.4 kilometers per hour. So each hour, he completes 22.4 km.

If he rides for 7 hours, he completes 22.4 * 7 = 156.8 km

So in 7 hours, he rides 156.8 kilometers.

Hope this helps! :)
6 0
4 years ago
Help?,?,?,?.!.??.?.?.?.?.?.
DaniilM [7]

Answer:

Step-by-step explanation:

b(a + 1) + a = b*a + b + a = ab + b + a

1) b(2a +1 ) = b*2a + b*1 = 2ab + b  Not equivalent.

2)a + (a +1)*b = a + ab+ b     Equivalent

3) (a +1)(b+ a) = a*(b +a) + 1*(b+a) = ab+ a² +b + a  Not equivalent.

4) (a + 1)b + a = ab+ b + a   Equivalent

5) a + b(a+1) = a +ab + b Equivalent

6) a + (a +1) + b = a + a + 1 + b = 2a + 1 +b  Not equivalent.

7) a(b +1) + b = ab + a + b  Equivalent

5 0
3 years ago
Find the distance between the pair of points.
SVEN [57.7K]

Answer:

Distance is \sqrt{290} units

Step-by-step explanation:

Use the distance formula which is d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} where d is the distance between points (x_1,y_1) and (x_2,y_2)

We are given that (x_1,y_1) is (-6,-23) and (x_2,y_2) is (-23,-24), therefore the distance between the two points is:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

d=\sqrt{(-23-(-6))^2+(-24-(-23))^2}

d=\sqrt{(-23+6))^2+(-24+23))^2}

d=\sqrt{(-17)^2+(-1)^2}

d=\sqrt{289+1}

d=\sqrt{290}

Therefore, the distance between (-6,-23) and (-23,-24) is \sqrt{290} units.

3 0
3 years ago
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