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Ymorist [56]
3 years ago
6

A bus can carry a maximum of 60 passengers. Each row accommodates the same number of passengers. If two rows are added then each

row would accommodate one passenger less for the bus to carry maximum number of passengers. Determine number of rows in the bus and no. Of passengers per row
Mathematics
1 answer:
VashaNatasha [74]3 years ago
7 0

Answer:

10 rows with 6 passengers per row

Step-by-step explanation:

Let x be the number of rows and y the number of passengers per row.

Then we can interpret the story as the following two equations:

xy=60

(x+2)(y-1)=60

Solving these two equations:

y=60/x

(x+2)(60/x-1)=60     (substitute y)

60 - x + 120/x - 2 = 60 (multiply by -x)

x² + 2x - 120 = 0     (factor)

(x-10)(x+12) = 0

x = 10

y = 60/10 = 6

and indeed 10 * 6 = 60 and also 12 * 5 = 60

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Is 1.9 < 1.39 which comparison is true?
alexandr1967 [171]

Answer:

1.9 is greater than 1.39 if that's what your asking?

7 0
3 years ago
Lily graphs segment LM. Then, she reflects the segment across the y-axis. Which statement compares the lengths of the segment LM
Free_Kalibri [48]

Solution

The reflection is a rigid transformation. This does not affect the length of a line segment.

Therefore, the line segments are equal.

Hence, LM = L'M'

Thank you. :)


8 0
3 years ago
Read 2 more answers
Point N(7, 4) is translated 5 units up.
lutik1710 [3]

It is given in the question that

Point N(7, 4) is translated 5 units up.

And we have to find the coordinates of its image after this transformation.

Since the point translated up by 5 units, so the x coordinate remains same and we have to add 5 to y coordinate.

So the new coordinate after the transformation is

N'(7+5,4)
\\
N'(12,4)

And that's the required coordinate  after the given transformation .

5 0
3 years ago
Ben was walking in Manhattan at a constant speed. He went along 5th avenue from 4th to 98th street. At 3:00 he was on 15th stree
muminat

Answer: The starting time is 2:27 and finishing time is 7:09.    


Step-by-step explanation: It is given that Ben started from 4th street and he finished at 98th street.

Also, at 3:00, he was on 15th street and at 4:30, he was on 45th street.

That is, time taken to cover (45-15), i.e., 30 streets is 90 minutes,                           so the time taken to cover 1 street is 3 minutes.

Therefore, Ben covers distance from one street to second in 3 minutes. Since he started from 4th street, and there are 11 streets to cover between 4 and 15, so Ben's starting time was (3:00 - 3×11 min) = 2:27.

And his finishing time was (4:30 + 3×53 min) = 7:09.

Again, the equation that tells us on what street 'N' he was after time 'T' of his starting can be written as

N=4+\dfrac{T}{3.}

Thus, the starting and finishing time was 2:27 and 7:09 respectively.



3 0
3 years ago
Write an equivalent algebraic equation for the sentence below.
tatuchka [14]

Answer:

x-7=13

Step-by-step explanation:

x-7= 13

hope that helps

5 0
3 years ago
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