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blagie [28]
3 years ago
5

D = {x|x is a whole number} E = {x|x is a perfect square between 1 and 9} F = {x|x is an even number greater than or equal to 2

and less than 9} Which of the following is an element of D ∩ (E ∩ F)?
Mathematics
1 answer:
ser-zykov [4K]3 years ago
4 0
<span>E = {x|x is a perfect square between 1 and 9} = {1,4
</span><span>F = {x|x is an even number greater than or equal to 2 and less than 9}
</span><span>D = {x|x is a whole number}
</span>
answer
D ∩ (E ∩ F) = 4
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Which algebraic expression represents the word expression "three times the square of a number, n, subtracted from 54"?
sveta [45]

Answer:

54 - 3n²

Step-by-step explanation:

Square of a number n = n²

Three times the square of n = 3*n² = 3n²

Expression:

54 - 3n²

3 0
3 years ago
Anthony has been saving nickels dimes quarters over the last year he knows that he has twice as many nickels as quarters. change
OLga [1]

Answer:

The number of nickel's coin is 150

The number of dime's coin is 35

The number of quarter's coin is 75

Step-by-step explanation:

Let

x ----> the number of nickel's coin

y ---> the number of dime's coin

z ---> the number of quarter's coin

Remember that

1\ nickel=\$0.05

1\ dime=\$0.10

1\ quarter=\$0.25

we know that

x+y+z=260 ----> equation A

0.05x+0.10y+0.25z=29.75 ----> equation B

x=2z ----> equation C

substitute equation C in equation A and equation B

2z+y+z=260

3z+y=260 ---> equation A1

0.05(2z)+0.10y+0.25z=29.75

0.35z+0.10y=29.75 -----> equation B1

Solve the system of equations A1 and B1 by graphing

Remember that the solution is the intersection point both graphs

The solution is the point (75,35)

see the attached figure

so

z=75, y=35

<em>Find the value of x</em>

x=2(75)=150

therefore

The number of nickel's coin is 150

The number of dime's coin is 35

The number of quarter's coin is 75

8 0
3 years ago
The total number of fans who went to watch professional soccer games in the last decade can be modeled by the function f(x)=x3+9
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Answer:

Step-by-step explanation:

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5 0
3 years ago
Evaluate the integral e^xy w region d xy=1, xy=4, x/y=1, x/y=2
LUCKY_DIMON [66]
Make a change of coordinates:

u(x,y)=xy
v(x,y)=\dfrac xy

The Jacobian for this transformation is

\mathbf J=\begin{bmatrix}\dfrac{\partial u}{\partial x}&\dfrac{\partial v}{\partial x}\\\\\dfrac{\partial u}{\partial y}&\dfrac{\partial v}{\partial y}\end{bmatrix}=\begin{bmatrix}y&x\\\\\dfrac1y&-\dfrac x{y^2}\end{bmatrix}

and has a determinant of

\det\mathbf J=-\dfrac{2x}y

Note that we need to use the Jacobian in the other direction; that is, we've computed

\mathbf J=\dfrac{\partial(u,v)}{\partial(x,y)}

but we need the Jacobian determinant for the reverse transformation (from (x,y) to (u,v). To do this, notice that

\dfrac{\partial(x,y)}{\partial(u,v)}=\dfrac1{\dfrac{\partial(u,v)}{\partial(x,y)}}=\dfrac1{\mathbf J}

we need to take the reciprocal of the Jacobian above.

The integral then changes to

\displaystyle\iint_{\mathcal W_{(x,y)}}e^{xy}\,\mathrm dx\,\mathrm dy=\iint_{\mathcal W_{(u,v)}}\dfrac{e^u}{|\det\mathbf J|}\,\mathrm du\,\mathrm dv
=\displaystyle\frac12\int_{v=}^{v=}\int_{u=}^{u=}\frac{e^u}v\,\mathrm du\,\mathrm dv=\frac{(e^4-e)\ln2}2
8 0
3 years ago
a group of fitness club members lose a combined total of 28 kilograms in 1 week. there are approximately 2.2 pounds in 1 kilogra
olga55 [171]
The group lose 8.8 pounds per day. For a detailed calculation, please refer to the attachment.
Download docx
6 0
3 years ago
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