<h2>
Answer:</h2>
<em><u>Recursive equation for the pattern followed is given by,</u></em>

<h2>
Step-by-step explanation:</h2>
In the question,
The number of interaction for 1 child = 0
Number of interactions for 2 children = 1
Number of interactions for 3 children = 5
Number of interaction for 4 children = 14
So,
We need to find out the pattern for the recursive equation for the given conditions.
So,
We see that,

Therefore, on checking, we observe that,

On checking the equation at the given values of 'n' of, 1, 2, 3 and 4.
<u>At, </u>
<u>n = 1</u>

which is true.
<u>At, </u>
<u>n = 2</u>

Which is also true.
<u>At, </u>
<u>n = 3</u>

Which is true.
<u>At, </u>
<u>n = 4</u>

This is also true at the given value of 'n'.
<em><u>Therefore, the recursive equation for the pattern followed is given by,</u></em>

<span>This question is asking you to substitute 0 for X and 5 for y in both equations. If the right hand value is equal to the left hand value after making the substitution, the answer is "yes". Otherwise, the answer is "no".
Substitute 0 for x and 5 for y in the first equation and then the second equation. Since 0 + 5 = 5 and -5*0 + 2*5 = 10 the answer </span>
Cars with a higher center of gravity are more likely to roll over (B) during a collision.
Answer:
I dont know how to do this
Answer:
2744 Rhinos will be left after 10 years
Step-by-step explanation:
This question has to do with exponential decay rate. We solve this using the formula:
P(t) = Po(1 - r)^t
Where P(t) = Amount left after t years
Po = Initial amount
r = Decay rate = 3.7% = 0.037
t = time in years = 10 years
P(t) = 4000(1 - 0.037)¹⁰
P(t) = 4000 × 0.963¹⁰
P(t) = 4000 × 0.6859032667003232
P(t) = 2743.6130668
Approximately = 2744 Rhinos will be left after 10 years