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Marrrta [24]
3 years ago
8

Which pair of monomials has the least common multiple (LCM) of 54x2y3?

Mathematics
2 answers:
katovenus [111]3 years ago
7 0

Answer:

The correct answer is option D.

18x2y, 27xy3

Step-by-step explanation:

<u>To find the LCM</u>

A).To find the Lcm of  (2xy, 27xy2)

LCM((2xy, 27xy2)  = 54xy^2

B).To find the  Lcm of  (3x2y3, 18x2y3)

LCM(3x2y3, 18x2y3)  = 18x^2y^4

C). To find the  Lcm of (6x2, 9y3)

LCM(6x2, 9y3)  = 18y^2y^

D). To find the  Lcm of (18x2y, 27xy3)

 LCM(18x2y, 27xy3) = 54x^2y^3

Therefore the correct answer is option D

18x2y, 27xy3

Lera25 [3.4K]3 years ago
6 0

ANSWER

The correct answer is D.

EXPLANATION

If we express the monomial,

18 {x}^{2} y

as product of primes, we obtain:

2 \times  {3}^{2}  \times  {x}^{2}y

If we express the monomial

27x {y}^{3}

as product of primes we obtain:

=  {3}^{3}  \times x {y}^{3}

The least common multiple of these two binomials is the product of the highest powers of the common factors.

The LCM is

= 2 \times  {3}^{3}  \times  {x}^{2} {y}^{3}

=54 {x}^{2} {y}^{3}

Therefore the correct answer is D.

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