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tia_tia [17]
2 years ago
15

Find each Quotient answer quick 2mins left don't troll

Mathematics
2 answers:
vagabundo [1.1K]2 years ago
5 0

Answer:

1) 9/50

2) 92/105

Step-by-step explanation:

1)\frac{3}{5} /4\frac{1}{6}  =\frac{3}{4} /\frac{25}{6} \\\\\frac{3}{4} *\frac{6}{25} =\frac{9}{50}

2) \frac{23}{7} /\frac{15}{4} =\frac{23}{7} *\frac{4}{15} \\\\=\frac{92}{105}

umka2103 [35]2 years ago
4 0

Answer:

18/125   92/105

Step-by-step explanation:

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A little help please
Dominik [7]

Answer: it’s 2, x = 2

Step-by-step explanation:

Hopes this helps !!!!

6 0
3 years ago
Which of the following expressions are equivalent to \left(9\dfrac{7}{8} + 2\dfrac{4}{5}\right)-\dfrac{1}{2}(9 87​ +2 54​ )− 21​
lora16 [44]

Answer:

12\dfrac{7}{40}

Step-by-step explanation:

The given expression is

\left(9\dfrac{7}{8} + 2\dfrac{4}{5}\right)-\dfrac{1}{2}

We need to find the simplified form of the given expression.

It can be rewritten as

\left(9+\dfrac{7}{8} + 2+\dfrac{4}{5}\right)-\dfrac{1}{2}

Combine integers and fractions separately.

(9+2)+(\dfrac{7}{8}+\dfrac{4}{5}-\dfrac{1}{2})

Taking LCM we get

11+\dfrac{35+32-20}{40}

11+\dfrac{47}{40}

In can be written as

11+\dfrac{40+7}{40}

11+1+\dfrac{7}{40}

12+\dfrac{7}{40}

12\dfrac{7}{40}

Therefore, the expression 12\dfrac{7}{40} is equivalent to the given expression.

5 0
3 years ago
64. In a pond of 1,600 fish, 25% of the fish are trout. The remaining fish are bass. How fewer trout are there than bass?
Nina [5.8K]

Answer:

There are 400 trout and 1,200 of them are bass.

4 0
3 years ago
Read 2 more answers
Can somebody help me please ​
aleksklad [387]

Answer:

I think it's -2

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Una empresa fabrica dos productos, X y Y. Cada cantidad del articulo X producida requiere dos horas de trabajo en una taladrador
Zarrin [17]

Answer:

la respuesta esta abajo

Step-by-step explanation:

a) Sea x el número del artículo x mientras que y representa el número del artículo y.

Dado que cada cantidad de artículo x requiere 2 horas de trabajo de perforación, mientras que cada cantidad de artículo y requiere 5 horas de trabajo de perforación. Hay un máximo de 40 horas disponibles, por tanto el modelo se da como:

2x + 5y ≤ 40

b) La trama se trazó utilizando la herramienta gráfica en línea de geogebra.

c) Para 10 unidades de X y 5 unidades de y:

2 (10) + 5 (5) = 45> 40

Por lo tanto, esto no sería posible porque requerirá 45 horas de perforación, lo que es más que el máximo de 40 horas disponibles.

8 0
3 years ago
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