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Eduardwww [97]
3 years ago
6

What is the taxidistance between A (1,5) and B (6,2)?A. 1B. 2 C. 8D. 14

Mathematics
1 answer:
bagirrra123 [75]3 years ago
4 0

we are given two points as

A (1,5) and B (6,2)

so,

x1=1 , y1=5

x2=6 , y2=2

now, we can use distance formula

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

now, we can plug values

and we get

d=\sqrt{(6-1)^2+(2-5)^2}

d=\sqrt{(5)^2+(3)^2}

so, we will get

d=\sqrt{34}.........Answer

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The x-coordinate of point P is positive, and the y-coordinate of point P is negative. In which quadrant is point P?
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Quadrant IV

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The given point have the x-coordinate to be positive and the y-coordinate to be negative.

In general, the point P(x,-y) lies in the fourth quadrant.

The reason is that, this quadrant contains the positive x-axis and the negative y-axis.

See attachment for diagram.

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Step-by-step explanation:

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A<br> B<br> 21<br> 48°<br> 6x-24<br> D<br> [?] &lt;&lt; &lt;[ ]<br> 11<br> C
r-ruslan [8.4K]

The shape in the figure is a composite shape with two triangles, and the inequality is 4 < x < 12

<h3>How to determine the range of value of x?</h3>

In the given figure, the side lengths AB and AD are equivalent.

This means that, we have the following angle relationship:

CAD < CAB

Substitute known values

6x - 24 < 48

Add 24 to both sides

6x < 72

Divide both sides by 6

x < 12

Also, we have the following angle relationship:

CAD > 0

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Add 24 to both sides

6x < 24

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brainly.com/question/21735282

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