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2 years ago

Help, I need the area

Mathematics

1 answer:

GenaCL600 [577]2 years ago

6 0

Answer- 314.16

Area =3.14 x r^2

Area =3.14 x 10^2= 314.16

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Find the volume and explain please ASAP.

olya-2409 [2.1K]

Answer:

1395in^3

Step-by-step explanation:

First find the volume of the cuboid, 15in x 9in x 7in = 945in^3

Then find the volume of the rectangular pyramid using the formula V=lwh/3, the total height is 17in so subtract the height of the cuboid from the total height, giving you 10in.

V=(15in)(9in)(10in)/3 = 450in^3

450in^3 + 945in^3 = 1395in^3

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3 years ago

In a class, 64 offers mathematics while 94 offers chemistry , How many will offer the both course?

Leokris [45]

Answer:

Step-by-step explanation:

94-64=30 will offer the same course because the chemistry offers ocerride the mathematics offers

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3 years ago

How to write slope intercept form of<br> y = -5/4 (x+4)

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Answer: y=−5/4x−5

Step-by-step explanation:

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2 years ago

You paint four walls. Each wall is a rectangle with a length of 20 feet and a height of 10 feet. One gallon of paint covers abou

Sphinxa [80]

Answer:

Step-by-step explanation:

20 x 10= 200 ft

1 gallon is 330 ft

paint 4 walls

200 x 4

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2 years ago

the height h(t) of a trianle is increasing at 2.5 cm/min, while it's area A(t) is also increasing at 4.7 cm2/min. at what rate i

nekit [7.7K]

Answer:

The base of the triangle decreases at a rate of 2.262 centimeters per minute.

Step-by-step explanation:

From Geometry we understand that area of triangle is determined by the following expression:

$A = \frac{1}{2}\cdot b\cdot h$ (Eq. 1)

Where:

$A$ - Area of the triangle, measured in square centimeters.

$b$ - Base of the triangle, measured in centimeters.

$h$ - Height of the triangle, measured in centimeters.

By Differential Calculus we deduce an expression for the rate of change of the area in time:

$\frac{dA}{dt} = \frac{1}{2}\cdot \frac{db}{dt}\cdot h + \frac{1}{2}\cdot b \cdot \frac{dh}{dt}$ (Eq. 2)

Where:

$\frac{dA}{dt}$ - Rate of change of area in time, measured in square centimeters per minute.

$\frac{db}{dt}$ - Rate of change of base in time, measured in centimeters per minute.

$\frac{dh}{dt}$ - Rate of change of height in time, measured in centimeters per minute.

Now we clear the rate of change of base in time within (Eq, 2):

$\frac{1}{2}\cdot\frac{db}{dt}\cdot h = \frac{dA}{dt}-\frac{1}{2}\cdot b\cdot \frac{dh}{dt}$

$\frac{db}{dt} = \frac{2}{h}\cdot \frac{dA}{dt} -\frac{b}{h}\cdot \frac{dh}{dt}$ (Eq. 3)

The base of the triangle can be found clearing respective variable within (Eq. 1):

$b = \frac{2\cdot A}{h}$

If we know that $A = 130\,cm^{2}$ , $h = 15\,cm$ , $\frac{dh}{dt} = 2.5\,\frac{cm}{min}$ and $\frac{dA}{dt} = 4.7\,\frac{cm^{2}}{min}$ , the rate of change of the base of the triangle in time is:

$b = \frac{2\cdot (130\,cm^{2})}{15\,cm}$

$b = 17.333\,cm$

$\frac{db}{dt} = \left(\frac{2}{15\,cm}\right)\cdot \left(4.7\,\frac{cm^{2}}{min} \right) -\left(\frac{17.333\,cm}{15\,cm} \right)\cdot \left(2.5\,\frac{cm}{min} \right)$

$\frac{db}{dt} = -2.262\,\frac{cm}{min}$

The base of the triangle decreases at a rate of 2.262 centimeters per minute.

6 0

2 years ago