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3 years ago

I NEED HELP ASAP WILL MARK BRAINLIST. NOTE: EVERYTHING IS ALREADY ANSWERD ALL I NEED HELP WITH IS QUESTION 8 AND 9 PLEASE

Mathematics

2 answers:

jonny [76]3 years ago

8 0

Answer:

8. Answer the original questions. (2 points: 1 point each question)

a) How long is each individual act?

Each individual act is 5 minutes.

b) How long is each group act?

Each group act is 10 minutes.

9. Discussion.

Discuss the reasonableness of your answers. (2 points: 1 point for each part)

a) Is the answer you found reasonable? Does it seem like enough time?

Yes, I believe the answer if found was reasonable. I think it is reasonable because 5 minutes seems to be enough time for an act with one person, and 10 minutes seems to be enough time for an act with multiple people.

Step-by-step explanation:

vivado [14]3 years ago

4 0

Answer:

THANKS A LOT!!!

Step-by-step explanation:

but can you help me on dividing 3,4,5, and 6 on its own answer. Because my teacher wont accept it. PLEASE help me on it. :(((

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The ratio of the rise to the run of the given triangle is __

Lemur [1.5K]

Answer:

1) 5/2 or 2.5

2) 5/2 or 2.5

Step-by-step explanation:

1) 5/2 = 2.5

2) 10/4 = 5/2 = 2.5

Because the hypotenuse of both are the segments of the same line and straight lines have the same gradient for all segments

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3 years ago

The sum of 3 consecutive even numbers of 78

Jet001 [13]

26, 24, 28 could be the answer

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3 years ago

Read 2 more answers

A glass paperweight has a composite shape: a square pyramid fitting exacty on top of an 8 centimeter cube. The pyramid has a hei

ArbitrLikvidat [17]

Answer:

Part 1) The volume of the paperweight is $576\ cm^{3}$

Part 2) The total surface area of the paperweight is $400\ cm^{2}$

Step-by-step explanation:

Part 1) what is the volume of the paperweight?

we know that

The volume of the paperweight is equal to the volume of the square pyramid plus the volume of the cube

step 1

Find the volume of the pyramid

The volume of the pyramid is equal to

$V=\frac{1}{3}BH$

where

B is the area of the square base

H is the height of the pyramid

$B=8^{2}=64\ cm^{2}$

$H=3\ cm$

substitute

$V=\frac{1}{3}(64)(3)=64\ cm^{3}$

step 2

Find the volume of the cube

The volume of the cube is equal to

$V=b^{3}$

$V=8^{3}=512\ cm^{3}$

step 3

Find the volume of the paperweight

$64\ cm^{3}+512\ cm^{3}=576\ cm^{3}$

Part 2) what is the total surface area of the paperweight?

we know that

The total surface area of the paperweight is equal to the surface area of 5 faces of the cube plus the lateral area of the pyramid

step 1

Find the surface area of 5 faces of the cube

$SA=5b^{2}$

$SA=5(8^{2})=320\ cm^{2}$

step 2

Find the lateral area of the pyramid

$LA=4[\frac{1}{2}bh]$

$LA=4[\frac{1}{2}(8)(5)]=80\ cm^{2}$

step 3

Find the total surface area of the paperweight

$320\ cm^{2}+80\ cm^{2}=400\ cm^{2}$

8 0

3 years ago

Mathematics, Help, not sure about my answer on this one

olga nikolaevna [1]

Answer:

F. 2 1/9

Step-by-step explanation:

Step 1: Substitute q

$r = 3(\frac{1}{3^n} )+2$

When you plug in <em>n</em> = 1, 2, 3:

n(1) = 3

n(2) = 2.11111

n(3) = 2.3333

So our answer is F.

3 0

3 years ago

√(5-22(√5)+121)<br> Simplify and show your steps

JulijaS [17]

The answer would be 8.7639

7 0

3 years ago