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3 years ago

I NEED HELP ASAP WILL MARK BRAINLIST. NOTE: EVERYTHING IS ALREADY ANSWERD ALL I NEED HELP WITH IS QUESTION 8 AND 9 PLEASE

Mathematics

2 answers:

jonny [76]3 years ago

8 0

Answer:

8. Answer the original questions. (2 points: 1 point each question)

a) How long is each individual act?

Each individual act is 5 minutes.

b) How long is each group act?

Each group act is 10 minutes.

9. Discussion.

Discuss the reasonableness of your answers. (2 points: 1 point for each part)

a) Is the answer you found reasonable? Does it seem like enough time?

Yes, I believe the answer if found was reasonable. I think it is reasonable because 5 minutes seems to be enough time for an act with one person, and 10 minutes seems to be enough time for an act with multiple people.

Step-by-step explanation:

vivado [14]3 years ago

4 0

Answer:

THANKS A LOT!!!

Step-by-step explanation:

but can you help me on dividing 3,4,5, and 6 on its own answer. Because my teacher wont accept it. PLEASE help me on it. :(((

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Answer:

B. 5.2

Step-by-step explanation:

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3 years ago

Solve the equation for z 5z-8=32 A. z=4 B. z=4.8 C. z=6 D. z=8

nadezda [96]

Answer:

Z=8 is the answer

Step-by-step explanation:

first, you add 8 to both sides which leaves you with 5z=40. then after that you divide both sides by 5 which leaves you with 5/5z = 40/5. then buy dividing 5 by 5 its leaves you with 1 which is equal to z because blank variables equal 1. On the other side if the equation 40 by 5 is 8 so that leaves you with z=8

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2 years ago

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Which role had the lowest median change TIMED TEST

svlad2 [7]

Answer:

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Step-by-step explanation:

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3 years ago

Solve........3 (5p - 3) = 5 (p - 1)

romanna [79]

Step 1: multiply the numbers in front of the parentheses with each term inside the parentheses

15p - 9 = 5p - 5

Step 2: get like terms on the same side

10p = 4

Step 3: divide both sides by 10

p = 4/10

Step 4: simplify

p = 2/5

7 0

3 years ago

What is the square root of -2i?

Studentka2010 [4]

Answer:

1-i and -1+i

Step-by-step explanation:

We are to find the square roots of $z=0-2i$ . First, convert from Cartesian to polar form:

$r=\sqrt{a^2+b^2}\\r=\sqrt{0^2+(-2)^2}\\r=\sqrt{0+4}\\r=\sqrt{4}\\r=2$

$\theta=tan^{-1}(\frac{b}{a})\\ \theta=tan^{-1}(\frac{-2}{0})\\\theta=\frac{3\pi}{2}$

$z=2(\cos\frac{3\pi}{2}+i\sin\frac{3\pi}{2})$

Next, use the formula $\displaystyle \sqrt[n]{r}\biggr[\cis\biggr(\frac{\theta+2\pi k}{n}\biggr)\biggr]$ where $\displaystyle k=0,1,2,...\:,n-1$ to find the square roots:

When k=1

$\displaystyle \sqrt[2]{2}\biggr[cis\biggr(\frac{\frac{3\pi}{2}+2\pi(1)}{2}\biggr)\biggr]$

$\displaystyle \sqrt{2}\biggr[cis\biggr(\frac{3\pi}{4}+\pi\biggr)\biggr]$

$\sqrt{2}\biggr(cis\frac{7\pi}{4}\biggr)$

$\sqrt{2}(\cos\frac{7\pi}{4}+i\sin\frac{7\pi}{4})\\ \\\sqrt{2}(\frac{\sqrt{2}}{2}-\frac{\sqrt{2}}{2}i)\\ \\1-i$

When k=0

$\displaystyle \sqrt[2]{2}\biggr[cis\biggr(\frac{\frac{3\pi}{2}+2\pi(0)}{2}\biggr)\biggr]$

$\sqrt{2}\biggr(cis\frac{3\pi}{4}\biggr)$

$\sqrt{2}(\cos\frac{3\pi}{4}+i\sin\frac{3\pi}{4})\\ \\\sqrt{2}(-\frac{\sqrt{2}}{2}+\frac{\sqrt{2}}{2}i)\\ \\-1+i$

Thus, the square roots of -2i are 1-i and -1+i

4 0

2 years ago