Answer:
D
Step-by-step explanation:
You are starting at 4 and going back 6 to -2.
So in order for us to know the area of the square that is not covered by the circle, we need to find first both the areas of the square and the circle.
So for the area of the square it is A = sxs. And for the circle is A = pi*r^2.
Let us find the area of the square first given that the side is 3 inches.
So A = 3*3
A = 9 square inches.
Next is the area of the circle. Since the center of the circle is the same with the center of the square, the radius would be 1.5.
SO, A = (3.14)(1.5)^2
A = 2.25 (3.14)
A = 7.065 square inches.
Next, we deduct the area of circle from area of square and the result would be 1.935 <span>in². So the answer for this would be option B.
Hope this answer helps.</span>
Answer:
0.61596
Step-by-step explanation:
Given that:
λ = 5 (5 errors per page)
Poisson distribution formula :
P(x = x) = (λ^x * e^-λ) / x!
Probability that page does not need to be retyped means that error on page is less than or equal to 5
P(x ≤ 5) = p(x = 5) + p(x = 4) +... + p(x = 0)
The individual probabilities can be obtained using the formula above or the use of a calculator
P(x ≤ 5) = 0.17547 + 0.17547 + 0.14037 + 0.08422 + 0.03369 + 0.00674
P(x ≤ 5) = 0.61596
You need to convert the second equation to slope/intercept form. The first equation is in that form already. Then you can compare slopes.
-6x + 8y = 14
8y = 6x + 14
y = (3/4)x + 14/8
SO THE SLOPE IS 3/4 which is the same as slope of equation 1
Therfore they are parallel.
Answer:
d. each trial has exactly two outcomes whose probabilities do not change
Step-by-step explanation:
A binomial experiment is one where there are exactly two outcomes for each trial and probability for getting success is constant in each trial.
In other words, each trial is independent of the other.
The trials need not be continuous nor time between trials to be constant.
Since trials are to be independent, each trial cannot influence the next.
Only option d is right.
d. each trial has exactly two outcomes whose probabilities do not change
Examples are tossing of coins, throwing dice, drawing cards or balls with replacement, etc
