Which expression is equivalent to (5^-2) (5^-1) -1/125 -1/5 1/125 1/5

What is the sum of the first two multiples of 8? A 8 B 16 C 24 D 32

pshichka [43]

The answer is 16 , 24

7 0

3 years ago

Read 2 more answers

33/7,158 A) 7,158/33= or B) 7,158 /33 = _ R _

Julli [10]

Answer:

What? HAHAHAHAHA it's the same. I mean the choices are the same

6 0

3 years ago

Supose that the half-life of a cesium is 30 years. If there were initially 1000g of the substance,

AveGali [126]

After 200 years, 9.84 grams of Cesium would remain.

Let N represent the amount of substance after t years

The half-life of a cesium is 30 years., hence, this can be represented by exponential function:

$N(t)=ab^t$

where a is the initial value and b is the multiplier.

There were initially 1000g of the substance

a) The exponential model for this situation is:

$N(t) =1000(\frac{1}{2} )^{\frac{1}{30} t}\\\\N(t) =1000(\frac{1}{2} )^{\frac{t}{30}$

b) After 200 years (t = 200), the amount of Cesium remaining is:

$N(200)=1000(\frac{1}{2} )^\frac{200}{30} \\\\N(200) = 9.84g$

Hence after 200 years, 9.84 grams of Cesium would remain

Find out more at: brainly.com/question/24710827

8 0

3 years ago

According to the United States Census Bureau, the average single-family home constructed in 2016 was 2,463 square feet. Carmen w

Dimas [21]

Using the t-distribution, it is found that the value of the test statistic is t = -87.3.

At the null hypothesis, it is tested if the mean is of 2,463 square feet, that is:

$H_0: \mu = 2463$

At the alternative hypothesis, it is tested if the mean is smaller, that is:

$H_1: \mu < 2463$ .

We have the standard deviation for the sample, hence, the t-distribution is used to solve this question.

The test statistic is given by:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

The parameters are:

$\overline{x}$ is the sample mean.

$\mu$ is the value tested at the null hypothesis.

s is the standard deviation of the sample.

n is the sample size.

The values of the parameters are: $\overline{x} = 1640, \mu = 2463, s = 66, n = 49$ .

Hence, the value of the test statistic is:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

$t = \frac{1640 - 2463}{\frac{66}{\sqrt{49}}}$

$t = -87.3$

To learn more about the t-distribution, you can take a look at brainly.com/question/25819230

7 0

2 years ago

At a putt putt course there are 50 yellow golf balls, 45 red golf balls, and 65 blue golf balls. What ratio compares the number

oksian1 [2.3K]

Blue balls : Total number.

Total number of balls = 50 + 45 + 65 = 160

Blue balls : Total number.

= 65: 160 Divide both by 5.
= 13 : 32

= 13/32. That is the ratio.

6 0

3 years ago