20/60 = 10/x
Cross multiply 10 with 60
600
Divide by 20
30.
It will take 30 minutes.
I think it’s the first one. 30:54 because 5 times 6 is 30 and 9 times 6 is 54.
Answer:
Therefore the concentration of salt in the incoming brine is 1.73 g/L.
Step-by-step explanation:
Here the amount of incoming and outgoing of water are equal. Then the amount of water in the tank remain same = 10 liters.
Let the concentration of salt be a gram/L
Let the amount salt in the tank at any time t be Q(t).

Incoming rate = (a g/L)×(1 L/min)
=a g/min
The concentration of salt in the tank at any time t is =
g/L
Outgoing rate =



Integrating both sides

[ where c arbitrary constant]
Initial condition when t= 20 , Q(t)= 15 gram


Therefore ,
.......(1)
In the starting time t=0 and Q(t)=0
Putting t=0 and Q(t)=0 in equation (1) we get









Therefore the concentration of salt in the incoming brine is 1.73 g/L
Answer:
8x + 12 = 12 + 8x
0 = 0
Step-by-step explanation:
Distribute then simplify
Answer:
268
Step-by-step explanation:
You would take 5356 and divide it by 20