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ipn [44]
3 years ago
5

Find the value of: a) 2x when x=5 b) 4y when = -3 c) 3z when z = 1.2

Mathematics
1 answer:
ohaa [14]3 years ago
5 0

Answer:

A. 10. B. -12. C. 3.6

Step-by-step explanation:

You will do this:

a) If x=5 (what about 2x)

=2x times 5 divide by x .That makes the answer 10

b) If y=-3(what about 4y)

=4y times -3 divide by y .That makes the answer -12.

c) If z=1.2(what about 3z)

=3z times 1.2divide by z. That makes the answer 3.6.

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Evaluate the given expression. Subscript 5 Baseline P Subscript 2 a. 40 c. 25 b. 32 d. 20
Leto [7]

Answer:

d. 20

Step-by-step explanation:

The given question implies 5 permutation 2, i.e _{5}P_{2}.

But,

_{n}P_{r} = \frac{n!}{(n - r)!}

So that for _{5}P_{2}, n = 5 and r = 2.

_{5}P_{2} = \frac{5!}{(5 - 2)!}

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Cancel out 3 and 2 with respect to the numerator and denominator.

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Therefore,

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So that the correct option is D.

6 0
3 years ago
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Given: ZDEF is a right angle. Using a paragraph proof, prove 41 is acute.
Slav-nsk [51]

Let G be some point on the diagonal line away from point E.

Angle DEG represents angle 1.

We're given that angle DEF is a right angle which means it's 90 degrees. Angle DEG is some angle smaller than 90 degrees. By definition, that must mean angle 1 is acute. Any acute angle is smaller than 90 degrees. There's not much else to say other than this is just a definition problem.

----------------

Extra side notes:

If angle 1 was a right angle, then that would mean angle GEF would have to be 0 degrees; however the diagram shows this isn't the case.

If angle 1 was obtuse, then there's no way we'd be able to fit it into angle DEF. In other words, there's no way to have an angle larger than 90 fit in a 90 degree angle.

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