3 years ago

Identify the equation in slope-intercept form for the line containing the point (−3,5) and parallel to y=−2/3x+53.

Mathematics

1 answer:

Alexeev081 [22]3 years ago

3 0

Answer:

y=−2/3x+3

Step-by-step explanation:

I graphed the point and the equation given below. I used the same slope in the new equation as the original equation. The y-intercept is 3 because the line goes through (0,3).

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Subtract the polynomials then simplify: 5x^5+4x^2-2x^6+6x^4 and 10x^2+10x^3+8x^6-9x^4

Jet001 [13]

Answer:

$\large\boxed{-10x^6+5x^5+15x^4-10x^3-6x^2}$

Step-by-step explanation:

$(5x^5+4x^2-2x^6+6x^4)-(10x^2+10x^3+8x^6-9x^4)\\\\=5x^5+4x^2-2x^6+6x^4-10x^2-10x^3-8x^6-(-9x^4)\\\\=5x^5+4x^2-2x^6+6x^4-10x^2-10x^3-8x^6+9x^4\\\\\text{combine like terms}\\\\=(-2x^6-8x^6)+5x^5+(6x^4+9x^4)-10x^3+(4x^2-10x^2)\\\\=-10x^6+5x^5+15x^4-10x^3-6x^2$