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Svetradugi [14.3K]
3 years ago
5

suppose Mina and two of her friends go to the movies.write an expression that could be used to find the total cost for them to g

o to the movies and buy one of each item.
Mathematics
2 answers:
Aleonysh [2.5K]3 years ago
4 0

Answer:

3(2.25+3.25+4.50+7.50)

Step-by-step explanation:

On this question we are using the distributive property, so if they are having three friends, you need to multiply the cost of each item by three. When we simplify this expression we get (3*2.25) + (3*3.25) + (3*4.50) + (3*7.50).

Then we find the answer to each part of the problem

3* 2.25=6.75

3*3.25=9.75

3*4.50=13.50

3*7.50=22.50

Then add: 6.75+9.75+13.50+22.50=$52.50.

Marizza181 [45]3 years ago
3 0
Let x represent the cost of the movie ticket and y represent the cost of a snack item. 3x + 3y
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An aeroplane X whose average speed is 50°km/hr leaves kano airport at 7.00am and travels for 2 hours on a bearing 050°. It then
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Answer:

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(b)39 degrees

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Plane X with an average speed of 50km/hr travels for 2 hours from P (Kano Airport) to point Q in the diagram.

Distance = Speed X Time

Therefore: PQ =50km/hr X 2 hr =100 km

It moves from Point Q at 9.00 am and arrives at the airstrip A by 11.30am.

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Using alternate angles in the diagram:

\angle Q=110^\circ

(a)First, we calculate the distance traveled, PA by plane Y.

Using Cosine rule

q^2=p^2+a^2-2pa\cos Q\\q^2=100^2+125^2-2(100)(125)\cos 110^\circ\\q^2=34175.50\\q=184.87$ km

SInce aeroplane Y leaves kano airport at 10.00am and arrives at 11.30am

Time taken =1.5 hour

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Average Speed of Y

=184.87 \div 1.5\\=123.25$ km/hr\\\approx 123$ km/hr (correct to three significant figures)

(b)Flight Direction of Y

Using Law of Sines

\dfrac{p}{\sin P} =\dfrac{q}{\sin Q}\\\dfrac{125}{\sin P} =\dfrac{184.87}{\sin 110}\\123 \times \sin P=125 \times \sin 110\\\sin P=(125 \times \sin 110) \div 184.87\\P=\arcsin [(125 \times \sin 110) \div 184.87]\\P=39^\circ $ (to the nearest degree)

The direction of flight Y to the nearest degree is 39 degrees.

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