Right cylinderSolve for lateral surfaceAL=2πrh<span><span><span>rRadius</span><span>hHeight</span></span><span><span>h</span>
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Answer:
Age of Anna = x years
Age of Jane i.e. Anna's sister = (x-y) years
a, What was the sum of their ages two years ago?
Solution,
Age of Anna two years ago = (x-2) years
Age of Jane two years ago = (x-y-2) years
Sum of their ages = x - 2 + x-y-2 = 2x - y -4
b. What will be the sum of their ages in 3 years?
Solution,
We have,
Present age of Anna = x years
Present age of Jane = (x-y) years
So,
Age of Anna after 3 years = (x+3) years
Age of Jane after 3 years = (x-y+3) years
Therefore,
Sum of their ages in 3 years = (x+3) +(x-y+3) = 2x - y+6
c. How old was Anna when Jane was born?
Solution,
Here,
According to question,
Jane is y years younger than Anna
So, Anna was y years when Jane was born.
[Suppose your age is 10 years and your brothers age is 14 years. You are 4 years younger than your brother. Also, his age was 4 years when you were born.]
Answer:
I hope this helps! <3
Step-by-step explanation:
To solve this problem you must apply the proccedure shown below:
1- By definition, the formula for calculate the i<span>nterquartile range is
I</span><span>nterquartile range=Q3-Q1
Where Q1 is the lower quartile and Q3 is the upper quartile.
2-Keeping this on mind, you have:
</span>Interquartile range=Q3-Q1
<span>
Q3=245
Q1=201
</span>Interquartile range=245-201
Interquartile range=44
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Therefore, the answer is: 44
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22 i think idk sorry if i’m wrong