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antiseptic1488 [7]
3 years ago
12

The vertices of triangle PQR are P(10,-6), Q(6,2), & R(4,-1). Describe a translation that places the image of the triangle e

ntirely in quatrant 2

Mathematics
1 answer:
Gnoma [55]3 years ago
5 0

Answer:

Translate 7 units up and then translate 11 units to the left.

Step-by-step explanation:

We have the triangle PQR having co-ordinates (10,6), (6,2) and (4,-1).

It is required to translate ΔPQR so that the resulting image is completely inside the 2nd quadrant.

So, for that we will apply the following sequence of translations:

1. Translate 7 units up.

This will give us the figure in the 1st quadrant having co-ordinates (10,1), (6,9) and (4,6).

2. Translate 11 units to the left

We will get the final triangle P'Q'R' with the co-ordinates P'(-1,1), Q'(-5,9) and R'(-7,6) as shown below.

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x = - 6

Step-by-step explanation:

A line with a slope of zero is a horizontal line parallel to the x- axis with equation

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8 0
3 years ago
1 1/3 divided by 3 + 1/3
Phantasy [73]
The first step to solve this problem is to convert the first mixed number to an improper fraction.
\frac{4}{3} ÷ 3 + \frac{1}{3}
Dividing is equivalent to multiplying with the reciprocal value,, so next you will need to change the signs.
\frac{4}{3} x \frac{1}{3} + \frac{1}{3}
Multiply the fractions
\frac{4}{9} + \frac{1}{3}
Finally,, add the two fractions together to get your final answer
\frac{7}{9}
This means that the correct answer to your question is \frac{7}{9} .
Let me know if you have any further questions
:)
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