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Anon25 [30]
4 years ago
6

There are 264 students going on a field trip to the city. If the school is only taking 8 buses, what is the total number of stud

ents that will be on each bus?
272
256
33
34
Mathematics
2 answers:
Naya [18.7K]4 years ago
7 0

Answer:

272

Step-by-step explanation:

Bond [772]4 years ago
3 0

Answer:

Step-by-step explanation:

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I need helpp hurry plzz!!!
wariber [46]

Answer:

B. 2x2

Step-by-step explanation:

5 0
2 years ago
Solve the following system:<br> y=1<br> y=-6x-5
Mandarinka [93]

Answer:

x = -1

y = 1

Step-by-step explanation:

<u><em>Since it gives you "y", plug in the number given into the equation:</em></u>

y = -6x - 5

1 = -6x - 5

<u><em>Then, add 5 to both sides:</em></u>

1 = -6x - 5

+5       + 5

________

6 = -6x

<em><u>Divide both sides by -6:</u></em>

6 = -6x

-1 = x

So now you have, x = -1 and y = 1

4 0
3 years ago
Read 2 more answers
Explain the rule in solving inequalities with a negative coefficient.
dimulka [17.4K]

Answer:

  the comparison must be reversed when multiplying by a negative

Step-by-step explanation:

The rules of equality apply to solving inequalities, with the exception that multiplication or division by a negative number reverses the sense of the comparison:

  -x > 1

  x < -1 . . . . . multiply both sides by -1

____

Effectively, multiplication (or division) by a negative number is equivalent to reflection across the origin. Things that were ordered left/right (on the number line) are ordered right/left after such a reflection:

  -2 < -1

  1 < 2

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<em>Additional comment</em>

Application of any function requires that you pay attention to ordering. Some functions naturally reverse the order; others do so only on specific domains.

Consider f(x) = 1/x.

  1 < 2

  f(1) > f(2) . . . . because the slope of the f(x) function is negative everywhere.

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<em>In the first and second quadrants</em>, the cosine function also reverses order.

  20° > 10°

  cos(20°) < cos(10°)

__

Probably the most commonly encountered function used with inequalities is the absolute value function.

  |x-3| > 2

This function has one domain where the slope is negative, and another domain where the slope is positive.

  For x < 3, the function negates its argument, so we have ...

     -(x -3) > 2

     -x +3 > 2

     -x > -1

     x < 1 . . . . . everywhere consistent with x < 3

  For x ≥ 3, the function does nothing, so we have ...

     x -3 > 2

     x > 5

  The solution to this absolute value inequality is (x < 1) ∪ (x > 5).

__

You can also resolve negative coefficients by adding the opposite. Addition and subtraction never require any change to the comparison operator.

  -x > 1

  0 > x +1 . . . . x is added

  -1 > x . . . . . . -1 is added

7 0
3 years ago
Jeanne babysits for $6 per hour. She also works as a reading tutor for $10 per hour. She is only allowed to work 20 hours per we
Ksenya-84 [330]

<u>Part a)</u> Use a system of inequalities to model the scenario

Let

x-------> represent babysitting hours

y-------> represent tutoring hours  

we know that

x+y \leq20 --------> inequality 1  

6x+10y \geq 75 --------> inequality 2

<u>Part b)</u> Use the model created in part A to create a graph representing Jeanne’s probable income earned and possible number of hours worked this week

we know that

x+y \leq20 --------> inequality 1

This inequality represent Jeanne’s possible number of hours worked this week

Using a graph tool

the solution of this inequality is the shaded area

see the attached figure N 1

6x+10y \geq 75 --------> inequality 2  

This inequality represent Jeanne’s probable income earned this week

Using a graph tool

the solution of this inequality is the shaded area

see the attached figure N 2

<u>Part c)</u> Analyze the set of coordinate values that represent solutions for the model created in part A. Choose one of the coordinates within the solution and algebraically prove that the coordinate represents a true solution for the model

we have the system of inequalities

x+y \leq20 --------> inequality 1

6x+10y \geq 75 --------> inequality 2

the solution of the system of inequalities is the shaded area

using a graph tool

see the attached figure N  3

Let

A(10,10) ------> see the attached figure N  3

The point belongs to the shaded area, so it is a system solution.

If the point is a solution, it must satisfy both inequalities.

<u>Prove algebraically </u>

A(10,10)

substitute the value of x and y in the inequalities

<u>inequality 1</u>

10+10 \leq20

20 \leq20 ------> is ok

<u>inequality 2</u>

6*10+10*10 \geq 75

160 \geq 75 -------> is ok

the point A satisfy both inequalities

therefore

the point A is a solution of the system

7 0
3 years ago
Lcm of 36 75 80 is what if you know plz send the answer​
DochEvi [55]

Answer:

3600

Step-by-step explanation:

lcm stands for "lowest common multiple"

the lcm is 3600 when done with the prime factorization process

6 0
3 years ago
Read 2 more answers
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