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3 years ago

Jeramy took 6 hours to read 222 pages of his book. What is Jeramy’s reading speed

Mathematics

2 answers:

hodyreva [135]3 years ago

6 0

Answer:

37 pages/hour

Step-by-step explanation:

To find the reading speed, we take the pages read and divide by the time it took.

222 pages/ 6 hours

37 pages/hour

DedPeter [7]3 years ago

4 0

Answer:

37 pages/hour

Step-by-step explanation:

This is a unit rate problem.

You are trying to find the number of pages per hour.

Divide the number of pages by the number of hours.

222 pages in 6 hours

(222 pages) / (6 hours) = 37 pages/hour

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In the given diagram, find the values of x, y, and z.

SSSSS [86.1K]

Answer:

a. x = 36°, y = 36°, z = 34°

Step-by-step explanation:

X = 36° because x and 144° are supplementary angles and the sum of supplementary angles = 180°

The sum of interior angles in a triangle is equal to 180° since one of the angle is given as 110° the sum of z and y must be equal to 70° the option that fits these qualities is a. x = 36°, y = 36°, z = 34°

5 0

3 years ago

Let f(x,y,z) = ztan-1(y2) i + z3ln(x2 + 1) j + z k. find the flux of f across the part of the paraboloid x2 + y2 + z = 3 that li

Sophie [7]

Consider the closed region $V$ bounded simultaneously by the paraboloid and plane, jointly denoted $S$ . By the divergence theorem,

$\displaystyle\iint_S\mathbf f(x,y,z)\cdot\mathrm dS=\iiint_V\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV$

And since we have

$\nabla\cdot\mathbf f(x,y,z)=1$

the volume integral will be much easier to compute. Converting to cylindrical coordinates, we have

$\displaystyle\iiint_V\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV=\iiint_V\mathrm dV$
$=\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=1}\int_{z=2}^{z=3-r^2}r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta$
$=\displaystyle2\pi\int_{r=0}^{r=1}r(3-r^2-2)\,\mathrm dr$
$=\dfrac\pi2$

Then the integral over the paraboloid would be the difference of the integral over the total surface and the integral over the disk. Denoting the disk by $D$ , we have

$\displaystyle\iint_{S-D}\mathbf f\cdot\mathrm dS=\frac\pi2-\iint_D\mathbf f\cdot\mathrm dS$

Parameterize $D$ by

$\mathbf s(u,v)=u\cos v\,\mathbf i+u\sin v\,\mathbf j+2\,\mathbf k$
$\implies\mathbf s_u\times\mathbf s_v=u\,\mathbf k$

which would give a unit normal vector of $\mathbf k$ . However, the divergence theorem requires that the closed surface $S$ be oriented with outward-pointing normal vectors, which means we should instead use $\mathbf s_v\times\mathbf s_u=-u\,\mathbf k$ .

Now,

$\displaystyle\iint_D\mathbf f\cdot\mathrm dS=\int_{u=0}^{u=1}\int_{v=0}^{v=2\pi}\mathbf f(x(u,v),y(u,v),z(u,v))\cdot(-u\,\mathbf k)\,\mathrm dv\,\mathrm du$
$=\displaystyle-4\pi\int_{u=0}^{u=1}u\,\mathrm du$
$=-2\pi$

So, the flux over the paraboloid alone is

$\displaystyle\iint_{S-D}\mathbf f\cdot\mathrm dS=\frac\pi2-(-2\pi)=\dfrac{5\pi}2$

6 0

3 years ago

For an A.P. ,The first two term are -3, 4. The 21st term is

Dahasolnce [82]

Answer:

The 21st term is 137.

Step-by-step explanation:

Arithmetic progression:

In an arithmetic progression the difference between consecutive terms is always the same, and its called common difference.

The nth term is given by:

$a_n = a_1 + (n-1)d$