Answer:
Some of the other answers are good examples of solving a system of three equations in three unknowns, which is what this problem is asking. Though the simplest way to solve this problem is actually to notice that, if we sum the three equations, we get:
X + Y = 10
X + Z = 20
+ Y + Z = 24
----------------
2X + 2Y + 2Z = 54
Factoring out the 2, we have 2(X + Y + Z) = 54, and dividing both sides by 2 reveals that X + Y + Z = 27.
Step-by-step explanation:
hopefully this helps
I believe it’s 13
you would substitute the x for 3
so you would multiply 4 by 3 and get 12
you then would add 1
Answer:
1156
Step-by-step explanation:
We know that,
( a + b ) ² = a² + 2ab + b²
We can follow the same method to find the value of this.
12² + 22²
( 12 + 22 ) ²
12² + 2 × 12 × 22 + 22²
144 + 24 × 22 + 484
144 + 528 + 484
672 + 484
<u>1156</u>
Let me know if you have any other questions. :)
You would just do 4 x 7, which means there are 28 combinations.
If the <em>n</em>-th term of the sequence is given by <em>n</em> ² - 2, then the 5th term is obtained by simply replacing <em>n</em> with 5 :
5² - 2 = 25 - 2 = 23
