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Ronch [10]
3 years ago
8

У = 3(х – 4)2 – 8 How do you write this in standard form

Mathematics
1 answer:
aniked [119]3 years ago
5 0

Answer:

y = 3x^2-24x+40

Step-by-step explanation:

Hi there!

Standard form: y=ax^2+bx+c

y = 3(x-4)^2-8

Solve (x-4)^2

y = 3(x^2-8x+16)-8

Multiply 3 by the parentheses

y = 3x^2-24x+48-8\\y = 3x^2-24x+40

I hope this helps!

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