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Katyanochek1 [597]
3 years ago
8

What is the leading coefficient in 1-2x+5x^4 when in standard form

Mathematics
1 answer:
Vera_Pavlovna [14]3 years ago
4 0
That's a lot of points for this question. You don't have to offer that much. 

Leading Coefficient: When written in standard form (starting with the variable with the highest power, going to the variable with the next highest power ... all the way down to a number with no variable), the leading coefficient is the number in front of the variable with the highest power. 

Let me put this less technically. Find the variable with the highest power. The number in front of that variable is the leading coefficient.

Write this in standard form. 5x^4 -2x + 1
The number in front of the x^4 is the answer.
5 <<<<< answer 
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Answer:

{(1, 0), (1, 1), (2,0), (2,1), (2, 2), (3,0), (3,1), (3,2), (3,3), (4, 0), (4,1), (4,2), (4,3), (4,4), (5,0), (5,1),(5,2), (5,3), (5,4), (5,5), (6,0), (6,1),(6,2), (6,3), (6,4), (6,5), (6,6)}

B.)

{(2,2), (3,2), (4,2), (4,4), (5,2), (5,4), (6,2), (6,4), (6,6)}

Step-by-step explanation:

Sample space :

Die roll, then number of coin tosses based on the outcome of the die roll, then number of heada from the toss(es) is recorded along with the outcome of the die roll.

{(1, 0), (1, 1), (2,0), (2,1), (2, 2), (3,0), (3,1), (3,2), (3,3), (4, 0), (4,1), (4,2), (4,3), (4,4), (5,0), (5,1),(5,2), (5,3), (5,4), (5,5), (6,0), (6,1),(6,2), (6,3), (6,4), (6,5), (6,6)}

Event that the total number of head is even:

{(2,2), (3,2), (4,2), (4,4), (5,2), (5,4), (6,2), (6,4), (6,6)}

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