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Katyanochek1 [597]
3 years ago
8

What is the leading coefficient in 1-2x+5x^4 when in standard form

Mathematics
1 answer:
Vera_Pavlovna [14]3 years ago
4 0
That's a lot of points for this question. You don't have to offer that much. 

Leading Coefficient: When written in standard form (starting with the variable with the highest power, going to the variable with the next highest power ... all the way down to a number with no variable), the leading coefficient is the number in front of the variable with the highest power. 

Let me put this less technically. Find the variable with the highest power. The number in front of that variable is the leading coefficient.

Write this in standard form. 5x^4 -2x + 1
The number in front of the x^4 is the answer.
5 <<<<< answer 
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A random sample of 20 recent weddings in a country yielded a mean wedding cost of $ 26,388.67. Assume that recent wedding costs
Makovka662 [10]

Answer:

a) 95% confidence interval for the mean​cost, μ​, of all recent weddings in this country = (22,550.95, 30,226.40)

.The​ 95% confidence interval is from $22,550.95 to $30,226.40.

b) For the interpretation of the result, option D is correct.

We can be​ 95% confident that the mean​ cost, μ​, of all recent weddings in this country is somewhere within the confidence interval.

c) Option B is correct.

The population mean may or may not lie in this​ interval, but we can be​ 95% confident that it does.

Step-by-step explanation:

Sample size = 20

Sample Mean = $26,388.67

Sample Standard deviation = $8200

Confidence Interval for the population mean is basically an interval of range of values where the true population mean can be found with a certain level of confidence.

Mathematically,

Confidence Interval = (Sample mean) ± (Margin of error)

Sample Mean = 26,388.67

Margin of Error is the width of the confidence interval about the mean.

It is given mathematically as,

Margin of Error = (Critical value) × (standard Error of the mean)

Critical value will be obtained using the t-distribution. This is because there is no information provided for the population mean and standard deviation.

To find the critical value from the t-tables, we first find the degree of freedom and the significance level.

Degree of freedom = df = n - 1 = 20 - 1 = 19.

Significance level for 95% confidence interval

(100% - 95%)/2 = 2.5% = 0.025

t (0.025, 19) = 2.086 (from the t-tables)

Standard error of the mean = σₓ = (σ/√n)

σ = standard deviation of the sample = 8200

n = sample size = 20

σₓ = (8200/√20) = 1833.6

99% Confidence Interval = (Sample mean) ± [(Critical value) × (standard Error of the mean)]

CI = 26,388.67 ± (2.093 × 1833.6)

CI = 26,388.67 ± 3,837.7248

99% CI = (22,550.9452, 30,226.3948)

99% Confidence interval = (22,550.95, 30,226.40)

a) 95% confidence interval for the mean​cost, μ​, of all recent weddings in this country = (22,550.95, 30,226.40)

.The​ 95% confidence interval is from $22,550.95 to $30,226.40.

b) The interpretation of the confidence interval obtained, just as explained above is that we can be​ 95% confident that the mean​ cost, μ​,of all recent weddings in this country is somewhere within the confidence interval

c) A further explanation would be that the population mean may or may not lie in this​ interval, but we can be​ 95% confident that it does.

Hope this Helps!!!

4 0
3 years ago
A great white shark weighted 4,302 pounds. This weight was 3 times the weight of a blue marlin fish. What was the weight of the
Sauron [17]

All you need to do is 4,302 divided by 3. You would get 1434 pounds. I did this in my head. You can split it to get 4,200 divided by 3 + 102 divided by 3. You get 1400 + 34 which is 1434.


7 0
3 years ago
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Can someone hep with this question please it seems like i can't get the answer correctly.ty!!
Mashcka [7]

Answer:

your answer will be 5

Step-by-step explanation:

hope it helps have a nice day/night ^_^

bye

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Log3 9=2

Explanation:
logo a= n <—> a = b^n

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I believe the answer is positive 8 :)
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2 years ago
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