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3 years ago

Least common multiple of 5 and 6

Mathematics

2 answers:

Hunter-Best [27]3 years ago

5 0

Least common multiple of 5 and 6.

5: 5, 10 , 15 , 20 , 25 , 30

6: 6, 12 ,18, 24, 30

30 is the least common multiple of 5 and 6.

Leya [2.2K]3 years ago

5 0

Find the prime factorization of 5

5 = 5

Find the prime factorization of 6

6 = 2 × 3

Multiply each factor the greater number of times it occurs in steps i) or ii) above to find the lcm:

LCM = 2 × 3 × 5

LCM = 30

Hope this helps!!!!^^

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Order these values from least to greatest.

liubo4ka [24]

Answer:

1 . 16

2 . 4

3 . 64

4 . -4

The fourth one goes first and then the second one and then the first one and then the third one.

3 0

2 years ago

Read 2 more answers

Find the sample size necessary in order to be 95% confident when determining the true mean weight within 2 units (EC2). Assume t

bogdanovich [222]

Answer:

Step-by-step explanation:

Given:

Margin of error (E) = 2

Sample variance $(s^{2})$ = 44

Confidence level = 95%

The z- value at 95% confidence level is 1.96.

The sample using the provided information can be calculated as:

$n=(\frac{z(s)}{E})^{2} \\n=\frac{z^{2} s^{2} }{E^{2} } \\n=\frac{1.96^{2} (44) }{2^{2} }\\n= 42.52\\n=43$

Hence, the correct option is (c) 43.

8 0

3 years ago

A square has an area of 64 square units. A cube has a volume of 64 cubic units. What is the difference in the side length of the

Rina8888 [55]

The formula in solving the area of a square is Area = a² where "a" is for the length of the side. The area formula in solving a cube is Area = 6a² where "a" is for the length of its side.
Area of square = a²
64 = a²
a = 8 units

Area of cube = 6a²
64= 6a²
a = 3.27 units

The difference of side of the square and side of the cube is shown below:
Difference = 8 - 3.27
Difference = 4.73 units.

The answer is 4.73 units.

4 0

3 years ago

PLS HELP!! determine which ordered pair is NOT a solution of y=-4x-2.

Alexxandr [17]

Your answer is B (3, -14)
Good Luck with your Test!!

6 0

3 years ago

Is anyone willing to help me with this? I tried adding this and still no answer. Please help..

GaryK [48]

Answer: C. (-4, -2)

Step-by-step explanation:

First, eliminate one of the variables and solve for the remaining variable:

2x - 5y = 2 → 3(2x - 5y = 2) → 6x - 15y = 6

3x + 2y = -16 → -2(3x + 2y = -16) → -6x - 4y = 32

-19y = 38

y = -2

Next, replace "y" with -2 into either of the original equations to solve for x:

2x - 5y = 2

2x - 5(-2) = 2

2x + 10 = 2

2x = -8

x = -4

x = -4, y = -2

Check:

Plug in the x- and y-values into the other original equation:

3x + 2y = -16

3(-4) + 2(-2) = -16

-12 + -4 = -16

-16 = -16 $\checkmark$

3 0

3 years ago