0.5 < x < 16.5 given: Two sides of triangle: 8.0 units and 8.5 units
Measure of third side = x
According to the triangle's inequality,
Sum of any two sides > third side. (i)
Difference between the sides < third side. (ii)
If x is the third side, then
x < 8+8.5 [Using (i)]
i.e. x< 16.5
Also, x > 8.5-8 [Using (ii)]
i.e. x> 0.5
Hence, Range of possible sizes for side x would be 0.5 < x < 16.5.
Answer: The correct option is A.
Explanation:
The slope intercept form is,
Where m is slope.
The point slope form is,
Where m is slope.
On Comparing the first equation with slope intercept form, we get m = -8.
On Comparing the second equation with point slope form, we get m = -2.
On Comparing the third equation with slope intercept form, we get m = 7.
On Comparing the Fourth equation with point slope form, we get m = 6.
The steepest line have greatest absolute slope value.
Since the equation 1 has greatest absolute slope value,i.e., 8 therefore option A is correct.
Answer:76.8
Step-by-step explanation:divde by 7 hope this helps god bless
Answer:
- slant height: 6 units
- lateral area: 108 square units
Step-by-step explanation:
<u>Given</u>
A right regular hexagonal pyramid with ...
- base side length 6 units
- base apothem 3√3 units
- height 3 units
<u>Find</u>
- lateral face slant height
- pyramid lateral surface area
<u>Solution</u>
a) The apothem (a) and height (b) of the pyramid are two legs of the right triangle having the slant height as its hypotenuse (c). The Pythagorean theorem tells us the relationship is ...
c = √(a² +b²) = √((3√3)² +3²) = √(27+9) = √36
c = 6
The slant height of the pyramid is 6 units.
__
b) The lateral surface area of the pyramid is the area of each triangular face, multiplied by the number of faces. The area of one face will be ...
A = (1/2)bh = (1/2)(6 units)(6 units) = 18 units²
Then the lateral surface area is 6 times this value:
SA = 6(18 units²) = 108 units²
The lateral surface area of the pyramid is 108 square units.
