Complete question :
Suppose there are n independent trials of an experiment with k > 3 mutually exclusive outcomes, where Pi represents the probability of observing the ith outcome. What would be the formula of an expected count in this situation?
Answer: Ei = nPi
Step-by-step explanation:
Since Pi represents the probability of observing the ith outcome
The number of independent trials n = k>3 :
Expected outcome of each count will be the product of probability of the ith outcome and the number of the corresponding trial.
Hence, Expected count (Ei) = probability of ith count * n
Ei = nPi
Answer:
b
Step-by-step explanation:
Answer:the answer is d
Step-by-step explanation:
Answer:
16m
8m
50.24m
200.96m^2
Step-by-step explanation:
13. 8*2=16
14. 8m
15. 2pi r = 2* pi* 8= 50.24
16. pi r^2 = pi * 8^2= 200.96m^2
Answer:
6 4/9
Step-by-step explanation:
You divide 58 and 8 and your answer would be 6.444444 repeating.
