What is the length of the hypotenuse of the right triangle ABC in the figure?
1 answer:
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Answer:
Step-by-step explanation:
I'm assuming you meant to type in
because you can only have removable discontinuities where there is a rational (fraction) function. Begin by factoring both the numerator and denominator to
and cancelling out like terms would have us eliminating the (x + 3). That is where there is a removable discontinuity. It leaves a hole. The other discontinuity, (x + 1) doesn't cancel out so it is a non-removable discontuinity, which is a vertical asymptote.
The removable discontinuity is at -3. There is no y value at x = -3 (remember there's only a hole here), because -3 causes the denominator to go to 0 and we all know that having a 0 in the denominator of a fraction is a big no-no!!!
[|] Answer [|]
[|] Explanation [|]
Rewrite the equation with parts separated:
8 + 7/9 - 3 - 2/3
Solve the whole number parts:
8 - 3 = 5
Solve the fraction parts:
7/9 - 2/3
Find LCD of 7/9 & 2/3
7/9 - 6/9 = 1/9
5 + 1/9 = 5 1/9