Answer:
PR= 8
ST=5
Step-by-step explanation:
PQ and PR are congruent so
2x=8
x=4
2*4=8
PR=8
ST and TU are congruent so
5z=2z+3
3z=3
z=1
5*1=5
ST=5
Answer:
1. r+s²=49
2. pq²=24
3. -4xy-6x²+2x²y-6y= -54
Step-by-step explanation:
1. r+s²=0+7²=49
2. pq²=(6)(2)²=6(4)=24
3. -4xy-6x²+2x²y-6y= -4(3)(2)-6(3)²+2(3)²(2)-6(2)
= -24-6(9)+2(9)(2)-12
= -24-54+36-12
= -78+36-12
= -42-12
= -54
Answer:
464 grams.
Step-by-step explanation:
Amount of substance:
The amount of substance after t years is given by an equation in the following format:

In which A(0) is the initial amount and r is the decay rate, as a decimal.
Co-60 has a half life of 5.3 years.
This means that:

We use this to find r. So



![\sqrt[5.3]{(1-r)^{5.3}} = \sqrt[5.3]{0.5}](https://tex.z-dn.net/?f=%5Csqrt%5B5.3%5D%7B%281-r%29%5E%7B5.3%7D%7D%20%3D%20%5Csqrt%5B5.3%5D%7B0.5%7D)


So

If a pellet that has been in storage for 26.5 years contains 14.5g of Co-60, how much of this radioisotope was present when the pellet was put in storage?
We have that
, and use this to find A(0). So



[tex]A(0) = 464[tex]
464 grams.
Answer:
133
Step-by-step explanation:
38/2=19
1 hour = 19 clean windows
7 hours *19 =133