question: An investment of $100 is now valued at $149.18 the interest rate is 8% per year, compounded continuously about how long has the money been invested
Answer:
5.2 years
Step-by-step explanation:
Applying
A = P(1+R/100)ⁿ.......................... Equation 1
Where A = amount, P = principle, R = rate, n = time.
From the question,
Given: A = $149.18, P = $100, R = 8%
Substitute these values into equation 1 and solve for n
149.18 = 100(1+8/100)ⁿ
149.18/100 = (1+8/100)ⁿ
1.4918 = (1+0.08)ⁿ
1.4918 = (1.08)ⁿ
Taking the Logarithm of both side
Log(1.4918) = Log(1.08)ⁿ
Log(1.4918) = nLog(1.08)
n = Log(1.4918)/Log(1.08)
n = 0.1737/0.0334
n = 5.2 years.
Answer:
y=0.6x+3
slope of the line 0.6 point (−3,−5)
(y+5)= 0.6(x+3)
The hypotenuse is 17
8+15+17=40
200/40=5
All sides of triangle
l\
75 l \85
| \
|__\
40
Answer:
y = -2/3x + 23/3
Step-by-step explanation:
Let equation of the line be y = mx + c
m = (3-5)/(7-4) = -2/3 gradient/slope formula
sub (4, 5)
5 = -2/3 (4) + c
c = 23/3
therefore, equation of the line is y = -2/3x + 23/3
Hope it helps! :)
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