Answer:
The third expression: (2x)^3
Step-by-step explanation:
Plug in 3 for x in each expression
2x^3
2(3)^3
Use PEMDAS
2 (3 × 3 × 3)
2 (9 × 3)
2 (27)
54
2x^3 + 5
(The last expression told us 2x^3 = 54 so feel free to use this information to make life easier)
54 + 5
59
(2x)^3
(2 × 3)^3
Use PEMDAS
6^3
6 × 6 × 6
36 × 6
216
(x - 1)^3
(3 - 1)^3
Use PEMDAS
2^3
2 × 2 × 2
4 × 2
8
216 is the greatest value so the third expression is the answer
Every even number is 2 away from the last.
0, 2, 4, 6, 8, 10, 12, 14...etc.
If we had an even number p, then the next three even numbers would be
p+2, p+4, and p+6.
<em>(If we had an odd number p, then the next three even numbers would be</em>
<em>p+1, p+3, and p+5. I'm not sure if p is even is implied in the question. Technically the answer would be p - p mod 2 + 2, where p is an interger...that gets into more technical function stuff, though.)</em>
Answer:
its c because parallel lines are lines that are always the same distance apart all of these are the same distance apart
hoped this helped let me know if it did
Answer:
i would tell you but what are the options if you tell me that ill gladly help you out
Step-by-step explanation:
would it be 25.3 or just 25
The answer would be 3n^2 + 2.
This can be found/proven by replacing "n" with term number (1,2,3,4...), then solving to get the final number. For example 3 * 1^2 + 2. You would first do 1^2, which is 1. Next, you would multiply 1 by 3, to get 3. Finally, you'd and the 2 to get 5. 5 is the 1st term, and you can use this same equation to get the rest of the terms you need.
I hope this helps!
