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erica [24]
3 years ago
8

6.746913 rounded to the nearest tenths place

Mathematics
2 answers:
svetoff [14.1K]3 years ago
8 0

Answer:

The answer is 7.

Step-by-step explanation:The tenths place is the first number after the decimal. In order to know what happens to the whole number you look at the number after the decimal and if its greater than 5 then goes up if no it stays the same. Ex: 2.5 rounded to the tenths place is 3

Slav-nsk [51]3 years ago
4 0

Answer :6.7

Step-by-step explanation:

Rounding decimals is very similar to rounding other numbers. If the hundredths and thousandths places of a decimal is forty-nine or less, they are dropped and the tenths place does not change.

For example, rounding 0.843 to the nearest tenth would give 0.8.

Read more on Brainly.com - brainly.com/question/12477494#readmore

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                                           = [- 12 ± √(144-64d) ] / (-32)
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The answer to your question is t = 3/8 ±√(9-4d) / 8
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The following definitions apply:

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Find a polynomial of degree 4 and the zeros are -2, 4, 4, 8
777dan777 [17]

Required polynomial of degree four having zeros as -2 , 4 , 4 , 8 is f(x)=x^{4}-14 x^{3}+48 x^{2}+32 x-256

<h3><u>Solution:</u></h3>

Need to determine a polynomial of degree 4 and the zeros are -2, 4 , 4 and 8

Let the required polynomial be represented by f(x)

The factor theorem describes the relationship between the root of a polynomial and a factor of the polynomial.

If the polynomial p(x) is divided by cx−d and the remainder, given by p(d/c), is equal to zero, then cx−d is a factor of p(x).

-2 is zero of a polynomial means when x = -2, f(-2) = 0, so from factor theorem we can say that  

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4 is zero of a polynomial means when x = 4, f(4) = 0 , so from factor theorem we can say that  

=> x = 4 that is x -4 = 0 is factor of polynomial f(x)

4 is zero of a polynomial means when x = 4, f(4) = 0 , so from factor theorem we can say that  

=> x = 4 that is x -4 = 0 is factor of polynomial f(x)

8 is zero of a polynomial means when x = 8, f(8) = 0 , so from factor theorem we can say that  

=> x = 8 that is x -8 = 0 is factor of polynomial f(x)

So now we have four factors of polynomial f(x) that are (x + 2), (x -4) , (x -4) and (x – 8)

And as given that degree of polynomial f(x) is 4  

Now f(x) is equal to product of factors

\begin{array}{l}{\Rightarrow f(x)=(x+2)(x-4)^{2}(x-8)} \\\\ {=>f(x)=(x+2)\left(x^{2}-8 x+16\right)(x-8)} \\\\ {=>f(x)=(x+2)\left(x^{3}-8 x^{2}+16 x-8 x^{2}+64 x-128\right)} \\\\ {=>f(x)=(x+2)\left(x^{3}-16 x^{2}+80 x-128\right)} \\\\ {=>f(x)=x\left(x^{3}-16 x^{2}+80 x-128\right)+2\left(x^{3}-16 x^{2}+80 x-128\right)} \\\\ {=>f(x)=x^{4}-16 x^{3}+80 x^{2}-128 x+2 x^{3}-32 x^{2}+160 x-256} \\\\ {=>f(x)=x^{4}-14 x^{3}+48 x^{2}+32 x-256}\end{array}

Hence required polynomial of degree four having zeros as -2 , 4 , 4 , 8 is f(x)=x^{4}-14 x^{3}+48 x^{2}+32 x-256

7 0
4 years ago
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