Answer:
A. VG = 80
B. Broad sense heritability = 0.80
C. Narrow sense heritability = 0.30
D. Average yield = 430 Units
Explanation:
A. Given that
VA = 30
VD = 50
VI = assumed not available
Therefore
Total genetic variance (VG) = VA + VD
= 30 + 50
= 80
VG = 80
B. Given that
VP = 100
VG = 80
Broad sense heritability, H2 = VG/VP
= 80/100
= 0.80
C. Given that
VA = 30
VP = 100
Narrow sense heritability, h2 = VA/VP
=30/100
= 0.30
D. The difference in selection = 500 - 400
= 100
Recall,
Selection response is heritability multiplied by selection differential.
That is
R = h2S
Selection differential = 100
Heritability h2 = 0.30
Selection response = 0.30 × 100
= 30units
Therefore, expected average yield = 400 + 30
= 430 Units
Answer:
undifferentiated; blood
Explanation:
Hematopoietic stem cells are undifferentiated cells that develop into blood cells.
Answer:
c. is a biotic factor within an ecosystem
Pyruvic acid binds with Coenzyme A (CoA) to form acetyle CoA. The acetyle CoA begins the Kreb Cycle.
Answer:
When a mustard plant seedling is transferred to an environment with higher levels of carbon dioxide, the new leaves have a lower stomata-to-surface-area ratio, it is because the concentration of carbondioxide is high in the surrounding so the plant produce small leaves having less number of stomata. If the concentration of carbondioxide is lower so big leaves are produced having maximum number of stomata.
