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tatiyna
3 years ago
15

Henrique Correa's bakery prepares all its cakes between 4 A.M. and 6 A.M.so they will be fresh when customers arrive. Day-old ca

kes are virtually always sold, but at a 50% discount off the regular $10 price. The cost of baking a cake is $7, and demand is estimated to be normally distributed, with a mean of 25 and a standard deviation of 8. What is the optimal stocking level? Refer to the standard normal table for z-values. The optimal stocking level for the bakery is cakes (round your response to the nearest whole number).
Business
1 answer:
masha68 [24]3 years ago
8 0

Answer:

The optimal stocking level for the bakery is cakes 27.

Explanation:

Cost c = $ 7

Selling price p = $ 10

salvage value s = $ 5

Mean = 25

Standard deviation \sigma = 8

Cu = underage cost

    = p-c

    = $10 - $7

    = $3

Co = overage cost

     = c-s

     = $7 - $5

     = $2

P\leq C_{u}/(C_{u}+C_{o})

P\leq3/(3+2)

= 0.6

By using normsinv() function in excel we to find the correct critical value

The Z value for the probability 0.6 is 0.2533

The optimal stocking level is

=\mu +z\sigma

= 25 + 0.2533 *8

= 27.02

The optimal stocking level of bakery is 27.02

Therefore, The optimal stocking level for the bakery is cakes 27.

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At 1.5 the average total cost is a minimum and the total cost will be 10.25 where the TC = total cost; x = output (in 1,000 units)

<h3>What are maxima and minima?</h3>

Maxima and minima of a function are the extremes within the range, in other words, the maximum value of a function at a certain point is called maxima and the minimum value of a function at a certain point is called minima.

We have a total cost function:

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At 1.5 the average total cost is a minimum.

Thus, at 1.5 the average total cost is a minimum and the total cost will be 10.25 where the TC = total cost; x = output (in 1,000 units)

Learn more about the maxima and minima here:

brainly.com/question/6422517

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