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nadezda [96]
4 years ago
15

Which expression is equivalent to 6a + 15? A. 6(a + 5) B. 3(2a + 5) C. 3(3a + 12) D. 6(a + 12) PLEASE HELP :)

Mathematics
2 answers:
makvit [3.9K]4 years ago
4 0
The answer is B

A. 6(a+5)
=6a+30 not equivalent to 6a+15
B.3(2a+5)
=6a+15 is equivalent
C.3(3a+12)
=9a+36 not equivalent
D.6(a+12)
=6a+72 not equivalent

So your answer is B
astraxan [27]4 years ago
3 0

Answer:

the answer is B im on the exam as well .

Step-by-step explanation:

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If a right triangle's hypotenuse is 17 units long, and one of its legs is 15 units long, how long is the other leg?
Vesna [10]

Answer:

8 units

Step-by-step explanation:

Hello!

So, there's a formula we can apply to right-angled triangles: Pythagorean's theorem. It states that  c = \sqrt{{a}^2 + b^{2} }, where <em>c</em> is the hypotenuse and <em>a</em> and <em>b </em>are the legs of the triangle.

So, from the problem,  if <em>c </em>= 17 and <em>a </em> = 15, then, we're solving for <em>b</em>. So we'll rewrite the theorem to solve for <em>b</em>.

{c}^2 = {a}^2+{b}^2\\{c}^2-{a}^2={b}^2\\{b} = \sqrt{{c}^2-{a}^2}

Okay, so now we have isolated the theorem for <em>b. Let's </em>plug in our values for <em>c </em>and <em>a</em>.

b = \sqrt{{17}^2-{15}^2}\\b = \sqrt{289-225}\\b = \sqrt{64}\\b = 8

So, using the theorem, we found <em>b</em> = 8. To check our work, let's plug in <em>b</em> and <em>a</em> and solve for <em>c.</em>

<em />c = \sqrt{{a}^2+{b}^2}}\\c = \sqrt{{15}^2+{8}^2}\\c = \sqrt{225+64}\\c = \sqrt{289}\\c = 17\\<em />

So, we got our hypotenuse to equal 17 units, which is correct! So, our <em>b</em> is correct too. Awesome

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Answer:

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Step-by-step explanation:

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