C=-3. (2c)^3
(2(-3))^3
(2-3)^3
(-1)^3
-1*-1*-1=
-1
Half the length of the curve which separates the 2 halves = 1/2 circumference of a circle with diameter 6 mm. = 1/2 * pi * d = 3pi mm
So the length of the line = 6pi = 18.85 mm to nearest hundredth. answer
The area of shaded region = 1/2 area of the circle = 1/2 pi r^2
= 1/2 * pi * 6^2
= 56.55 mm^2 to nearest hundredth answer
Answer:
72 cm
Step-by-step explanation:
Find the radius using the given information
308=1/2(πr^2)
r^2=616/π
r=14
The perimeter is πr + 2r so plug in 14
π(14) + 2(14)
43.96+28=71.96
Perpendicular bisectors have a particular property: if AB is a perpendicular bisector of CD, then every point lying on AB has the same distance from C and D.
In your case, we have that every point lying on AC has the same distance from B and D.
So, in particular, we have EB=ED, because E lies on AC.
Moreover, since AC is a perpendicular bisector, it is the height of the triangle (if we choose BD as base), and it bisects BD: this means that the triangle is isosceles, so AD=AB.
This means that triangles ABE and ADE have:
- AD=AB because ABD is isosceles
- EB=ED because AC is the perpendicular bisector of BD
- AE in common
So, their sides are all equal, and thus they are congruent.
