Answer:
3,340$
Step-by-step explanation:
e(8000)=.0675(8000)+2800
e(8000)=540+2800
e(8000)=3340
Frogs are at the pond = 12.
Given,
There are some frogs and some lily pads at a pond. If lily pads with frogs on them have two frogs each, then there are 3 lily pads with no frogs on them. If each lily pad has exactly one frog on it, then there are 3 frogs with no lily pad.
= 2( n-3) = n+3
= 2n -6 = n+3
=> n = 9
9 pads, 12 frogs.
Hence, Frogs are at the pond = 12.
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Answer:
3Ax-6x = 15
3x(A-2)=15
If A were 2, the left side of the equation would be 0 and it wouldn't equal 15 no matter what the value of x is. So A is 2
The smallest positive integer that the intermediate value theorem guarantees a zero exists between 0 and a is 3.
What is the intermediate value theorem?
Intermediate value theorem is theorem about all possible y-value in between two known y-value.
x-intercepts
-x^2 + x + 2 = 0
x^2 - x - 2 = 0
(x + 1)(x - 2) = 0
x = -1, x = 2
y intercepts
f(0) = -x^2 + x + 2
f(0) = -0^2 + 0 + 2
f(0) = 2
(Graph attached)
From the graph we know the smallest positive integer value that the intermediate value theorem guarantees a zero exists between 0 and a is 3
For proof, the zero exists when x = 2 and f(3) = -4 < 0 and f(0) = 2 > 0.
<em>Your question is not complete, but most probably your full questions was</em>
<em>Given the polynomial f(x)=− x 2 +x+2 , what is the smallest positive integer a such that the Intermediate Value Theorem guarantees a zero exists between 0 and a ?</em>
Thus, the smallest positive integer that the intermediate value theorem guarantees a zero exists between 0 and a is 3.
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Answer:
A
Step-by-step explanation:
Hope it will help you......