What's the question, I can't see images on my school laptop
Answer:
729 is a perfect square
Step-by-step explanation:
because 27 * 27 = 729
Answer:
Hey there!
False. The product of a positive number and a negative number is always NEGATIVE.
Let me know if this helps :)
Answer:
1. Cosθ / SineθCosθ
2. Sineθ / Cos²θSineθ
3. Cosθ / Sineθ
4. Cos²θ + Sin²θ – Sin²θ
Step-by-step explanation:
1. SecθCotθ
Recall
Sec θ = 1/Cos θ
Cot θ = 1/Tan θ
But Tan θ = Sine θ / Cos θ
Thus,
Cot θ = 1 ÷ Sine θ / Cos θ
Cot θ = 1 × Cos θ / Sine θ
Cot θ = Cos θ / Sine θ
Therefore,
SecθCotθ = 1/Cos θ × Cos θ / Sine θ
SecθCotθ = Cosθ / SineθCosθ
2. SecθTanθCscθ
Recall
Sec θ = 1/Cos θ
Tan θ = Sine θ / Cos θ
Csc θ = 1/Sine θ
Thus,
SecθTanθCscθ =
1/Cosθ × Sineθ/Cosθ × 1/Sineθ
= Sineθ / Cos²θSineθ
3. Cscθ/Secθ
Recall
Csc θ = 1/Sine θ
Sec θ = 1/Cos θ
Thus,
Cscθ/Secθ = 1/Sine θ ÷ 1/Cos θ
= 1/Sine θ × Cos θ
= Cosθ / Sineθ
4. Cosθ / Secθ
Recall
Sec θ = 1/Cos θ
Cosθ / Secθ = Cosθ ÷ 1/Cosθ
= Cosθ × Cosθ
= Cos²θ
Recall
Cos²θ + Sin²θ = 1
Cos²θ = 1 – Sin²θ
But
1 = Cos²θ + Sin²θ
Thus,
Cos²θ = Cos²θ + Sin²θ – Sin²θ
Therefore,
Cosθ / Secθ = Cos²θ + Sin²θ – Sin²θ
Answer:
Here's one way to do it
Step-by-step explanation:
1. Solve the inequality for y
5x - y > -3
-y > -5x - 3
y < 5x + 3
2. Plot a few points for the "y =" line
I chose
\begin{gathered}\begin{array}{rr}\mathbf{x} & \mathbf{y} \\-2 & -7 \\-1 & -2 \\0 & 3 \\1 & 8 \\2 & 13 \\\end{array}\end{gathered}
x
−2
−1
0
1
2
y
−7
−2
3
8
13
You should get a graph like Fig 1.
3. Draw a straight line through the points
Make it a dashed line because the inequality is "<", to show that points on the line do not satisfy the inequality.
See Fig. 2.
4. Test a point to see if it satisfies the inequality
I like to use the origin,(0,0), for easy calculating.
y < 5x + 3
0 < 0 + 3
0 < 3. TRUE.
The condition is TRUE.
Shade the side of the line that contains the point (the bottom side).
And you're done (See Fig. 3).