Answer:A = b x h
Step-by-step explanation:
I can't see the problem but i can give help u have to follow the formuls
Side 1 = short side = 2x-3
side 2 = longer side = (short side) + 6 = (2x-3)+6 = 2x+3
side 3 = side 2 = 2x+3
Side 2 and side 3 are the longer two congruent sides
Add up the three sides and set them equal to the given perimeter of 33. Solve for x
(side1)+(side2)+(side3) = perimeter
(2x-3)+(2x+3)+(2x+3) = 33
(2x+2x+2x) + (-3+3+3) = 33
6x+3 = 33
6x+3-3 = 33-3
6x = 30
6x/6 = 30/6
x = 5
If x = 5, then the longer sides are 2*x+3 = 2*5+3 = 10+3 = 13 inches each
(note: the short side is 2*x-3=2*5-3=10-3 = 7 inches)
Answer: 13 inches
The function of the water balloon is an illustration of a quadratic function.
The balloon will splat on the ground after 2.5 seconds
The function is given as:

When the balloon splats on the ground, the value of h(t) is 0.
So, we have:

Expand the expression

Factorize the above expression

Factor out 2t - 5 in the 2t - 5

Split the equation into 2

Rewrite as:

Solve for t

The value of t cannot be less than 0 i.e. negative.
So, we have

Divide 5 by 2

Hence, the balloon will splat on the ground after 2.5 seconds
Read more about quadratic functions at:
brainly.com/question/11631534
Answer:
<h2><em><u>
x = 52</u></em></h2>
Step-by-step explanation:
<em><u>Known:</u></em>
What to find = x
Exterior angle = 142
Right angle = 90
<em><u>Unknown:</u></em>
what unknown value is = ?
Interior angle = ?
<em><u>1. Find the angle of the interior angles.</u></em>
180 - 142 = 38
<em><u>2. Add the two known angles</u></em>
38 + 90 = 128
<em><u>3. Subtract from 180</u></em>
180 - 128 = 52
<h2><em><u>
x = 52 is the answer.</u></em></h2>
Hope this helped,
Kavitha Banarjee
We have the equation:

We know two points and we will use them to calculate the parameters a and b.
The point (0,3) will let us know a, as b^0=1.

Now, we use the point (2, 108/25) to calcualte b:
![\begin{gathered} y=3\cdot b^x \\ \frac{108}{25}=3\cdot b^2 \\ 3\cdot b^2=\frac{108}{25} \\ b^2=\frac{108}{25\cdot3}=\frac{108}{3}\cdot\frac{1}{25}=\frac{36}{25} \\ b=\sqrt[]{\frac{36}{25}} \\ b=\frac{\sqrt[]{36}}{\sqrt[]{25}} \\ b=\frac{6}{5} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20y%3D3%5Ccdot%20b%5Ex%20%5C%5C%20%5Cfrac%7B108%7D%7B25%7D%3D3%5Ccdot%20b%5E2%20%5C%5C%203%5Ccdot%20b%5E2%3D%5Cfrac%7B108%7D%7B25%7D%20%5C%5C%20b%5E2%3D%5Cfrac%7B108%7D%7B25%5Ccdot3%7D%3D%5Cfrac%7B108%7D%7B3%7D%5Ccdot%5Cfrac%7B1%7D%7B25%7D%3D%5Cfrac%7B36%7D%7B25%7D%20%5C%5C%20b%3D%5Csqrt%5B%5D%7B%5Cfrac%7B36%7D%7B25%7D%7D%20%5C%5C%20b%3D%5Cfrac%7B%5Csqrt%5B%5D%7B36%7D%7D%7B%5Csqrt%5B%5D%7B25%7D%7D%20%5C%5C%20b%3D%5Cfrac%7B6%7D%7B5%7D%20%5Cend%7Bgathered%7D)
Then, we can write the equation as: