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Dafna1 [17]
2 years ago
8

Three salesmen work for the same company, selling the same product. And, although they are all paid on a weekly basis, each sale

sman earns his paycheck differently. Salesman A works strictly on commission. He earns $65 per sale, with a maximum weekly commission of $1,300. Salesman B earns a weekly base salary of $300, plus a commission of $40 per sale. There are no limits on the amount of commission he can earn. Salesman C does not earn any commission. His weekly salary is $900. For each salesman, write an equation showing the relationship between their weekly paycheck amount, p, and the number of sales, s, they had that week. Graph the three equations you just wrote for each salesman if they have between 0 and 20 sales in a week. Graph all three equations on the same graph . Make sure you label each line with the salesman it represents, as well as label the axes. Note: The independent variable is s, and the dependent variable is p.
Mathematics
1 answer:
yanalaym [24]2 years ago
3 0
GIVEN:
<span>Salesman A works strictly on commission. He earns $65 per sale, with a maximum weekly commission of $1,300.
Salesman B earns a weekly base salary of $300, plus a commission of $40 per sale. There are no limits on the amount of commission he can earn.
Salesman C does not earn any commission. His weekly salary is $900.

Salesman A: 1300 </span>≤ 65S
Salesman B: P = 40S + 300
Salesman C: P = 900

Salesman A can only have 20 sales. 1,300/65 = 20. It should not go beyond that because it will go beyond the limit of 1,300 per week.

Salesman B will earn 1,100 for 20 sales. P = 40(20) + 300 = 800 + 300 = 1,100.

Salesman C will earn 900 regardless if he had 0 or 20 sales for the week.

You can do your own graph using my equations.

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Answer:

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Step-by-step explanation:

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kifflom [539]

Answer:

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Step-by-step explanation:

Given:

A box has a volume of 308 cm cubed.

Its height is 4 cm greater than its length.

Its length is 3 cm greater than its width.

Question asked:

What is the width of the box?

<u>Solution</u>:

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