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3 years ago

In the equation y=mx +b what si b

Mathematics

1 answer:

Goshia [24]3 years ago

5 0

Answer:

B is the y-intercept. Where you start your slope.

Step-by-step explanation:

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Find the missing measure if a and b are the legs of the right triangle and c is the hypotenuse, with a = 11 and c =18.

never [62]

Answer:

$\sqrt{203}$

Step-by-step explanation:

1. $11^{2} + b^{2} = 18^{2}$

2. $b^{2} =203$

3. b = $\sqrt{203}$

Can't be simplified.

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3 years ago

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John was swimming for hour anda half hours at a speed of 2 miles per hour.How far did he swim?

Marrrta [24]

Answer:

3 miles

Step-by-step explanation:

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3 years ago

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Help please Im bout to fail.....

max2010maxim [7]

Answer:

it's the second to last one on the right side

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3 years ago

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Point G is located at (6, 2) on the coordinate plane. Point G is reflected over the y -axis to create point G^ prime . What orde

Lilit [14]

Answer:

The ordered pair that best describes the location of G' is (-6,2).

Step-by-step explanation:

Reflecting a point over the y-axis:

When a point (x,y) is reflected over the y-axis, it's x coordinate is multiplied by -1, while the y-coordinate stays the same. Thus:

(x,y) -> (-x,y).

Point G is located at (6, 2)

When reflected over the y-axis:

G'(-6,2).

The ordered pair that best describes the location of G' is (-6,2).

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2 years ago

A consumer organization inspecting new cars found that many had appearance defects (dents, scratches, paint chips, etc.). While

Murljashka [212]

Answer:

The expected number of appearance defects in a new car = 0.64

standard deviation = 0.93(approximately)

Step-by-step explanation:

Given -

7% had exactly three, 11% exactly two, and 21% only one defect in cars.

Let X be no of defects in a car

P(X=3) = .07 , P(X=2) = .11 , P(X=3) = .21

P(X=0 ) = 1 - .07 - .11 - .21 = 0.61

The expected number of appearance defects in a new car =

E(X) = $\nu$ = $= \sum X P(X) =3\times 0.07 + 2\times0.11 + 3\times0.21 + 0\times0.61$ = 0.64

$\sigma^{2}$ = variation of E(X) = $\sum (X - \nu) ^{2}P(X)$ = $(3 - 0.64) ^{2}\times0.07 + (2 - 0.64) ^{2}\times0.11 + (1 - 0.64) ^{2}\times0.21 + (0 - 0.64) ^{2}\times0.61$

= $(2.36) ^{2}\times0.07 + (1.36) ^{2}\times0.11 + (.36) ^{2}\times0.21 + ( 0.64) ^{2}\times0.61$ = 0.8704

standard deviation = $\sqrt{\sigma^{2}}$ = $\sqrt{0.8704^{2}}$ = 0.93(approximately)

4 0

3 years ago