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2 years ago

2x+3=-7 what does x equal

Mathematics

1 answer:

ollegr [7]2 years ago

5 0

Answer:-5

Step-by-step explanation:

2x+3=-7

2x=-7-3

x=-10/2

so,

x=-5

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I don't know why it is faced that way but help plz

Nady [450]

Answer: x > 5

Step-by-step explanation: You need to isolate x. First, distribute the 1/2 into the parentheses. You will get:

4x + x + 2 > 12

Combine like terms.

5x + 2 > 12

Subtract 2 from each side.

5x > 10

Divide by 5 on each side.

X > 2

Since x is by itself, that is the answer.

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3 years ago

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Solve the following system of equations graphically on the set of axes below.

ikadub [295]

Answer:

Step-by-step explanation:

I can't use the same graph that you have supplied, but I can show you what the answer looks like. Just use two points from my answer that will fit on your graph. Suggest points

Red line: (7,0) and (3,6)

Blue line: (3,0) and (0,3)

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2 years ago

Keeping the properties of exponents in mind to what power must your raise the expression 7 1/2 to get 7 as a result

exis [7]

Answer:

x=2

Step-by-step explanation:

(7^ (1/2))ˣ = 7¹

1/2 *x =1

x =2

3 0

3 years ago

Write the given differential equation in the form L(y) = g(x), where L is a linear differential operator with constant coefficie

melamori03 [73]

Answer:

The complete solution is

$\therefore y= Ae^{3x}+Be^{-\frac13 x}-\frac43$

Step-by-step explanation:

Given differential equation is

3y"- 8y' - 3y =4

The trial solution is

$y = e^{mx}$

Differentiating with respect to x

$y'= me^{mx}$

Again differentiating with respect to x

$y''= m ^2 e^{mx}$

Putting the value of y, y' and y'' in left side of the differential equation

$3m^2e^{mx}-8m e^{mx}- 3e^{mx}=0$

$\Rightarrow 3m^2-8m-3=0$

The auxiliary equation is

$3m^2-8m-3=0$

$\Rightarrow 3m^2 -9m+m-3m=0$

$\Rightarrow 3m(m-3)+1(m-3)=0$

$\Rightarrow (3m+1)(m-3)=0$

$\Rightarrow m = 3, -\frac13$

The complementary function is

$y= Ae^{3x}+Be^{-\frac13 x}$

y''= D², y' = D

The given differential equation is

(3D²-8D-3D)y =4

⇒(3D+1)(D-3)y =4

Since the linear operation is

L(D) ≡ (3D+1)(D-3)

For particular integral

$y_p=\frac 1{(3D+1)(D-3)} .4$

$=4.\frac 1{(3D+1)(D-3)} .e^{0.x}$ [since $e^{0.x}=1$ ]

$=4\frac{1}{(3.0+1)(0-3)}$ [ replace D by 0 , since L(0)≠0]

$=-\frac43$

The complete solution is

y= C.F+P.I

$\therefore y= Ae^{3x}+Be^{-\frac13 x}-\frac43$

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Alexxandr [17]

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