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Maru [420]
4 years ago
13

The angle of elevation to the top of the Empire State Building in New York is found to be 11 degrees from the ground at a distan

ce of 1 mi from the base of the building. Using this information, find the height of the Empire State Building.

Mathematics
2 answers:
GaryK [48]4 years ago
5 0

Answer:

The height of the Empire State Building is 0.1944miles (1026.43ft)

Step-by-step explanation:

This question can be answered using <u>Trigonometry</u>, and we can draw a sketch from the information provided. There is one attached.

From the problem's statement, we know that the <em>angle of elevation to the top of the building from the ground</em> is α=11°, and there is <em>a distance of </em><em>1mi</em><em> from the base of the building</em>.

As we can see from the sketch, the given information permits us to draw a right-angled triangle and we can find the <em>height H</em> using trigonometric functions.

We need to remember that in a right-angled triangle, <em>tangent function</em> is defined as \\ tan(\alpha)=\frac{opposite}{adjacent}, that is, the <em>ratio</em> of the <em>opposite side</em> to the angle in question (in this case α) to the <em>adjacent side</em> to this angle.

The opposite side of angle α is H, and the adjacent side is the distance given, that is, 1 mile.

Looking at the sketch attached, we can see that \\tan(11)=\frac{H}{1mi}, and that \\ H=tan(11)*1mi=0.1944*1mi=0.1944mi, so the height of the Empire State Building, according to this information, is H = 0.1944mi.

The value of the tangent of the angle α was rounded to tan(11°)=0.1944.

A value of tan(11°)=0.19438030913771848424...could be found in WolframAlpha's website.

To find the equivalent distance in <em>feet</em>, we know that there are 5280ft in a mile, so, using <em>proportions</em>:

\\ \frac{5280ft}{1mi}=\frac{X}{0.1944mi} ⇒

\\ X =\frac{5280ft*0.1944mi}{1mi}, which results in 1026.43ft.

This problem could be solved also using the <em>Law of Sines</em>, but using more steps, and knowing that the sum of the internal angles of a rigth-angled triangle equals 180°.

Svetllana [295]4 years ago
3 0
Draw a picture of a building and a one mile (or 5280 feet) distance to a point from the base of the building. 

The angle of elevation is given as 11° and we want the height of the building or x. 

tan(11°) = x/5280 

5280 tan(11°) = x 

1026.3 feet = x 


I hope my answer has come to your help. Thank you for posting your question here in Brainly.
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Using the normal distribution, it is found that:

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c) 0.6811 = 68.11% probability that x is between 60 and 110.

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In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

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In this problem:

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Item a:

This probability is <u>1 subtracted by the p-value of Z when X = 60</u>, thus:

Z = \frac{X - \mu}{\sigma}

Z = \frac{60 - 87}{25}

Z = -1.08

Z = -1.08 has a p-value of 0.1401.

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0.8599 = 85.99% probability that x is more than 60.

Item b:

This probability is the <u>p-value of Z when X = 110</u>, thus:

Z = \frac{X - \mu}{\sigma}

Z = \frac{110 - 87}{25}

Z = 0.92

Z = 0.92 has a p-value of 0.8212.

1 - 0.8212 = 0.1788.

0.1788 = 17.88% probability that x is less than 110.

Item c:

This probability is the <u>p-value of Z when X = 110 subtracted by the p-value of Z when X = 60</u>.

From the previous two items, 0.8212 - 0.1401 = 0.6811.

0.6811 = 68.11% probability that x is between 60 and 110.

Item d:

This probability is <u>1 subtracted by the p-value of Z when X = 125</u>, thus:

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Z = \frac{125 - 87}{25}

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0.0643 = 6.43% probability that x is greater than 125.

A similar problem is given at brainly.com/question/24863330

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