b=5, commutative property
c=3, associative property
Answer:
1.
2.
Step-by-step explanation:
f(x) = + 1
putting f (x) = y
y = + 1
= ( y-1)
x =
Therefore = =
g (x) =
putting g(x) = y
y =
= (x-4)
x =
( o
2. (f o g)(x) = (√x-4)²+1) = x-4+1
(f o g)(x) = x-3
Let y = x - 3
x = y + 3
Or
By De Moivre's formula, the <em>cubic</em> roots of the <em>complex</em> number are 3 + i 4, - 4.96 + i 0.60 and 1.96 - i 4.60.
<h3>How to find the cube root of a complex number</h3>
Herein we have a <em>complex</em> number in <em>rectangular</em> form, from which we need its magnitude (r) and direction (θ) and the De Moivre's formula as well. The <em>root</em> formula is introduced below:
, for k ∈ {0, 1, ..., n - 1} (1)
Where n is the grade of the complex root.
The magnitude and direction of the <em>complex</em> number are 125 and 0.886π radians, respectively. Thus, by the De Moivre's formula we obtain the following three solutions:
k = 0
z₁ = 2.997 + i 4.002
k = 1
z₂ = - 4.964 + i 0.595
k = 2
z₃ = 1.967 - i 4.597
By De Moivre's formula, the <em>cubic</em> roots of the <em>complex</em> number are 3 + i 4, - 4.96 + i 0.60 and 1.96 - i 4.60.
To learn more on complex numbers: brainly.com/question/10251853
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Answer:
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