From the equation we see that the center of the circle is at (-2,3) and the radius is 9.
So using the distance formula we can see if the distance from the center to the point (8,4) is 9 units from the center of the circle...
d^2=(8--2)^2+(4-3)^2 and d^2=r^2=81 so
81=10^2+1^2
81=101 which is not true...
So the point (8,4) is √101≈10.05 units away from the center, which is greater than the radius of the circle.
Thus the point lies outside or on the exterior of the circle...
Answer:
Answer: g(x)=. Step-by-step explanation: We are given that: f(x)=x². We have to find g(x). Since, we are given that g(3)=1. Hence, we will ... · g of x would equal (1/3x)^2 because if x was 6 y, g(x), would be 4
Step-by-step explanation:
Answer:
[7-2x+5y-(x-y) -[5x+3y-7]
= 7-2x+5y-x+y-5x-3y+7
=7+7-2x-x-5x+5y+y-3y
=14-8x+3y
=-8x+3y+14
Step-by-step explanation:
14.29 * .0725 = 1.04
1.04 * 3 = 3.12
