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melisa1 [442]
3 years ago
8

Which whole number property is represented?

Mathematics
2 answers:
Novay_Z [31]3 years ago
6 0
This would be the commutative property. i hope this helps!!
Hatshy [7]3 years ago
5 0
Commutative Property of Multiplication
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What would be the circumference of a circle with a radius of 5?
lilavasa [31]

Answer: 10pi

Step-by-step explanation:

C = 2(pi)r

r = 5

2*(pi)*5 = C

10pi = C is the exact answer

If we make 3.14 for the pi substitution, then:

2*3.14*5=C

31.5 = C

4 0
3 years ago
a centroid separates a median into two segments. which of the following is the ratio of the length of the shorter segment to the
olga2289 [7]
The answer is 2:1.

The centroid separates the median, or the point from the midpoint of a side of a triangle with its opposite angle, at a ratio of 2:1, meaning that one segment is 1/3 the length of the median and the other segment is 2/3 the length of the median. 
3 0
3 years ago
What system shows the correct numbers to multiply by the coefficients in order to eliminate y from the first two
Ann [662]

Answer:

3 (5x+2y = 0)

2 (2x – 3y = -19)

Step-by-step explanation:

5x+2y=0 (1)

2x-3y=-19 (2)

To eliminate y from the first two equation when applying the linear combination method

We will multiply y Equation (1) and (2) with 3 and 2 respectively so that the coefficients of y in the two equations +6 and -6 respectively

3(5x+2y=0)

2(2x-3y=-19)

We have,

15x+6y=0 (3)

4x-6y= -38 (4)

Add Equation (3) and (4)

19x=-38

x= -2

Substitute x= -2 into (1)

5x+2y=0

5(-2)+2y=0

-10+2y=0

-10= -2y

y=-10/-2

=5

y=5, x=-2

3 0
3 years ago
What is 0.69696969 expressed as the quotient of two integers in simplest form?
timofeeve [1]

When written as the quotient of two integers,

           0.69696969  =  <em>69,696,969 / 100,000,000 .</em>

<u>If</u> you had said that the ' 69 ' keeps repeating forever and never ends,
then that decimal would represent the fraction
                                                                       23 / 33 .
                                                    

3 0
3 years ago
Prove that root 7 is irrational by the method of contradiction
Alchen [17]

Let assume that \sqrt7 is a rational number. Therefore it can be expressed as a fraction \dfrac{a}{b} wherea,b\in\mathbb{Z} and \text{gcd}(a,b)=1.

\sqrt7=\dfrac{a}{b}\\\\7=\dfrac{a^2}{b^2}\\\\a^2=7b^2

This means that a^2 is divisible by 7, and therefore also a is divisible by 7.

So, a=7k where k\in\mathbb{Z}

(7k)^2=7b^2\\\\49k^2=7b^2\\\\7k^2=b^2

Analogically to a^2=7b^2 ------- b^2 is divisible by 7 and therefore so is b.

But if both numbers a and b are divisible by 7, then \text{gcd}(a,b)=7 which contradicts our earlier assumption that \text{gcd}(a,b)=1.

Therefore \sqrt7 is an irrational number.

8 0
3 years ago
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