All categories

3 years ago

A shose box measures 15in.by 7in.by 4 an half

Mathematics

1 answer:

Svet_ta [14]3 years ago

4 0

The volume is 472.5in^3.

You might be interested in

Find the volume of each figure. Round your answer to the nearest hundredth, if necessary.<br><br>

bija089 [108]

Formula for volume of cone:

V = $\pi r^{2} \frac{h}{3}$

r = 6 km

h = 12 km

V = $\pi 6^{2} \frac{12}{3}$

V = $\pi 36*4$

V = $\pi 144$

V = 452.389 km^3 <----------------------Using the calculators pi button

V = 452.16 km^3 <-------------------------Using 3.14 for pi

Hope this helped!

~Just a girl in love with Shawn Mendes

7 0

3 years ago

Select the correct answer.<br> What is the value of g(2)

Mariulka [41]

Answer:

answer is D

Step-by-step explanation:

we must calculate it from this equation :

x³ -9x²+27x-25 then

${2}^{3} -( 9 \times 4 )+ (27 \times 2) - 25 = 1$

4 0

3 years ago

What is the area of a circle if its radius is 5? Step-by-step explanation too.

sesenic [268]

Answer:

Step-by-step explanation:

Area = 3.14r^2

Area = 3.14(5)^2

Area = 3.14(25)

Area = 78.5

4 0

3 years ago

Some banks now use continuous compounding of an amount invested. In this case, the equation that models the value of an initial

Komok [63]

Answer:

In this case, the equation that models the value of an initial investment of P dollars in t years at an annual interest rate of r is given by A = Pert.

Step-by-step explanation:

4 0

2 years ago

Which of the following is an extraneous solution of (45-3x)^1/2=x-9?

Iteru [2.4K]

Answer:

C. x =3

Step-by-step explanation:

Extraneous solution is that root of a transformed equation that doesn't satisfy the equation in it's original form because it was excluded from the domain of the original equation.

Let's solve the equation first

$\sqrt{45-3x} = x-9\\Taking\ square\ on\ both\ sides\\{(\sqrt{45-3x})}^2 = {(x-9)}^2\\45-3x = x^2-18x+81\\0 = x^2-18x+81-45+3x\\x^2-15x+36 = 0\\x^2-12x-3x+36 = 0\\x(x-12)-3(x-12) = 0\\(x-3)(x-12)\\x-3 = 0\\=> x =3\\x-12 = 0\\x = 12\\We\ will\ check\ the\ solutions\ one\ by\ one\\So,\\for\ x=3\\\sqrt{45-3(3)} = 3-9\\\sqrt{45-9} = -6\\\sqrt{36}= -6\\6\neq -6\\For x=12\\\sqrt{45-3(12)} = 12-9\\\sqrt{45-36} = 6\\\sqrt{36}= 6\\6=6$

Hence, we can conclude that x=3 is an extraneous solution of the equation ..

3 0

4 years ago