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2 years ago

What is the volume of a sphere with a diameter of 10 m, rounded to the nearest tenth of a cubic meter

Mathematics

1 answer:

kirill [66]2 years ago

4 0

Answer:

4188.8 cm^3

Step-by-step explanation:

We can calculate the volume of a sphere by using the following equation:

$\frac{4}{3}\pi r^{3}$

(r=radius)

so let's just plug in what we know

4/3(pi)(10)^3

we can calculate this with a calculator to get 4188.8 cm^3.

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A car is 180 inches long. A truck is 75% longer than the car. How long is the truck?

LUCKY_DIMON [66]

Answer:

Step-by-step explanation:

The truck is 315 inches long

7 0

3 years ago

A small cube with side length 6y is placed inside a larger cube with side length 4x^2. What is the difference in the volume of t

olasank [31]

Answer:

64x⁶ - 216y³

Step-by-step explanation:

The formula for the volume of a cube is

Vol. = l³

For the large cube,

V =(4x²)³

V = 64x⁶

For the small cube,

v =(6y)³

v = 216y³

The difference in volume is

Diff. = 64x⁶ - 216y³

5 0

3 years ago

Read 2 more answers

(-2,-4) and (6,7)<br> Need help show steps too

Verdich [7]

Answer:

Step-by-step explanation:

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3 0

2 years ago

How can i differentiate this equation?

Dmitry_Shevchenko [17]

$\bf y=\cfrac{2x^2-10x}{\sqrt{x}}\implies y=\cfrac{2x^2-10x}{x^{\frac{1}{2}}} \\\\\\ \cfrac{dy}{dx}=\stackrel{\textit{quotient rule}}{\cfrac{(4x-10)(\sqrt{x})~~-~~(2x^2-10x)\left( \frac{1}{2}x^{-\frac{1}{2}} \right)}{\left( x^{\frac{1}{2}} \right)^2}} \\\\\\ \cfrac{dy}{dx}=\cfrac{(4x-10)(\sqrt{x})~~-~~(2x^2-10x)\left( \frac{1}{2\sqrt{x}} \right)}{\left( x^{\frac{1}{2}} \right)^2} \\\\\\ \cfrac{dy}{dx}=\cfrac{(4x-10)(\sqrt{x})~~-~~\left( \frac{2x^2-10x}{2\sqrt{x}} \right)}{x}$

$\bf\cfrac{dy}{dx}=\cfrac{(4x-10)(\sqrt{x})~~-~~\left( \frac{2x^2-10x}{2\sqrt{x}} \right)}{x} \\\\\\ \cfrac{dy}{dx}=\cfrac{ \frac{(4x-10)(\sqrt{x})(2\sqrt{x})~~-~~(2x^2-10x)}{2\sqrt{x}}}{x} \\\\\\ \cfrac{dy}{dx}=\cfrac{(4x-10)(\sqrt{x})(2\sqrt{x})~~-~~(2x^2-10x)}{2x\sqrt{x}}$

$\bf \cfrac{dy}{dx}=\cfrac{(4x-10)2x~~-~~(2x^2-10x)}{2x\sqrt{x}}\implies \cfrac{dy}{dx}=\cfrac{8x^2-20x~~-~~(2x^2-10x)}{2x\sqrt{x}} \\\\\\ \cfrac{dy}{dx}=\cfrac{8x^2-20x~~-~~2x^2+10x}{2x\sqrt{x}} \implies \cfrac{dy}{dx}=\cfrac{6x^2-10x}{2x\sqrt{x}} \\\\\\ \cfrac{dy}{dx}=\cfrac{2x(3x-5)}{2x\sqrt{x}}\implies \cfrac{dy}{dx}=\cfrac{3x-5}{\sqrt{x}}$