What kind of work is that ?
78 = 1.50x + 2.50x + 4(x/2)) + 3((x/2) + 1))
78 = 4x + 4(x/2) + 3((x/2)+1)
78 = 4x + 2x + (3(x/2) + 3)
78 = 6x + 1.5x + 3
75 = 7.5x
10 = x
Mr. Abernathy bought 10 wrenches at $1.50, 10 wrenches at $2.50, 5 wrenches at $4, and 6 wrenches at $3.
Answer:
c. (12.12, 18.48)
Step-by-step explanation:
Hello!
The study variable is X: number of times a racehorse is raced during its career.
The average number is X[bar]= 15.3 and the standard deviation is S= 6.8 obtained from a sample of n=20 horses.
To estimate the population mean you need that the variable has a normal distribution, in this case, we have no information about its distribution so I'll assume that it has a normal distribution. With n=20 the most accurate statistic to use for the estimation is a Students-t for one sample, the formula for the interval is:
X[bar] ± 

[15.3 ± 2.093 *
]
[12.12; 18.48]
Using a significance level of 95% you'd expect that the true average of times racehorses are raced during their career is included in the interval [12.12; 18.48].
I hope it helps!
First step: x= ± √ 121
Second step and correct answer: x= ± 11
Because: x^2 = x= ± √