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Nikolay [14]
3 years ago
12

Michael estimated his mass as 8 kilograms.Is his estimate reasonable?Justify your answer.

Mathematics
2 answers:
DerKrebs [107]3 years ago
5 0
Yes, his estimate is reasonable. But only if Michael is less than 2 years old.
matrenka [14]3 years ago
3 0

Answer:

Yes, his answer is reasonable if he is very young.

Explanation:

If he is at a very young age then his answer would be yes reasonable, but seeing as he calculated this on his own, most likely not.

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Slope=
elixir [45]

Point 1 (0, - 2)

Point 2 (8,0)


Slope = (y2-y1)/(x2-x1)= (0-(-2))/(8-0)=2/8=1/4

y-intercept (from the Point 1 (0, - 2)) is -2.


Equation : y=(1/4)x - 2


Coordinates to test are (4,-1).


y=(1/4)x - 2

-1=(1/4)*4 -2

-1=1-2

-1=-1 True

3 0
4 years ago
To help vegetables stay fresh longer, Liam’s family maintains storage near their home. The total volume of the root cellar is 95
Helga [31]

To help vegetables stay fresh longer, Volume of storage of 951 cubic feet is equal to 26.929 m^3

<u>Solution:</u>

Given that to help vegetables stay fresh longer, Liam’s family maintains storage.

Total volume of root cellar that is storage is 951 cubic feet.

Also given that 1 foot = 0.3048 meters

need to find the volume of storage in cubic meter that is m^3

\begin{array}{l}{\text { As } 1 \text { foot }=0.3048 \mathrm{m}} \\\\ {\Rightarrow 1 \text { foot } \times 1 \text { foot }=0.3048 \mathrm{m} \times 0.3048 \mathrm{m}} \\\\ {\Rightarrow 1 \text { foot } \times 1 \text { foot } \times 1 \text { foot }=0.3048 \mathrm{m} \times 0.3048 \mathrm{m} \times 0.3048 \mathrm{m}} \\\\ {=1 \mathrm{foot}^{3}=0.0283 \mathrm{m}^{3}} \\\\ {\Rightarrow 1 \text { cubic feet }=0.0283 \mathrm{m}^{3}}\end{array}

\text { So } 951 \text { cubic feet }=951 \times 0.0283 \mathrm{m}^{3}=26.929 \mathrm{m}^{3}

Hence volume of storage of 951 cubic feet is equal to 26.929 m^3

7 0
3 years ago
I think I know this much so far for A (but I could be wrong):
Eduardwww [97]
Part A. You have the correct first and second derivative.

---------------------------------------------------------------------

Part B. You'll need to be more specific. What I would do is show how the quantity (-2x+1)^4 is always nonnegative. This is because x^4 = (x^2)^2 is always nonnegative. So (-2x+1)^4 >= 0. The coefficient -10a is either positive or negative depending on the value of 'a'. If a > 0, then -10a is negative. Making h ' (x) negative. So in this case, h(x) is monotonically decreasing always. On the flip side, if a < 0, then h ' (x) is monotonically increasing as h ' (x) is positive.

-------------------------------------------------------------

Part C. What this is saying is basically "if we change 'a' and/or 'b', then the extrema will NOT change". So is that the case? Let's find out

To find the relative extrema, aka local extrema, we plug in h ' (x) = 0
h  ' (x) = -10a(-2x+1)^4
0 = -10a(-2x+1)^4
so either
-10a = 0 or (-2x+1)^4 = 0
The first part is all we care about. Solving for 'a' gets us a = 0. 
But there's a problem. It's clearly stated that 'a' is nonzero. So in any other case, the value of 'a' doesn't lead to altering the path in terms of finding the extrema. We'll focus on solving (-2x+1)^4 = 0 for x. Also, the parameter b is nowhere to be found in h ' (x) so that's out as well. 
6 0
3 years ago
TRUE or FALSE: In the quarter circle, the radius is 4 cm and the diameter is 8 cm.
viktelen [127]

Answer: False.

Step-by-step explanation:

There does not exist a "quarter circle" as a circle with a radius of 4 units, the only notable circle that does exist is the unit circle, that is the circle where the radius is equal to 1, represented by the equatin x^2 + y^2 = 1

The term "quarter circle" actually does refer to a fourth part of a circle, not to a circle of radius 4.

So the statement is false

6 0
3 years ago
What is the least common multiple (LCM) of 7 and 8? will give brainlest if answered in 1 minute
attashe74 [19]

Answer:

56.

Step-by-step explanation:

3 0
3 years ago
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