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2 years ago

I know I’m asking a lot but please help reeeeeee and idk I just picked random that’s why d is circled

Mathematics

1 answer:

PolarNik [594]2 years ago

7 0

Answer:

D is actually correct

It wouldn't be A or C and in the phrase it says the sum so it is not B so it is D.

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A defunct website listed the "average" annual income for Florida as $35,031. What is the role of the term average in statisti

rodikova [14]

Answer:

Step-by-step explanation:

Average is the sum of the items in a data divided by the number of items in the data. The role of average is to determine a representative value for the given set of data. What average refers to in statistics is the arithmetic mean. There are other types of mean as well. Therefore, what we are referring to in this scenario is the arithmetic mean. Therefore, another term should not be used in place of average. Therefore, the correct option is

C. The term average is often used in statistics to represent the mean.

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3 years ago

what is the equation of the line that is perpendicular to the line y=3/5x+10 and passes through the point (15,-5)

riadik2000 [5.3K]

Answer:

$y = -\frac53x + 20$

Step-by-step explanation:

Hello!

A line that is perpendicular to another has an opposite-reciprocal slope.

Meaning:

Flip the sign (+/-)
Flip the fraction

The slope perpendicular to 3/5 would be -5/3.

We can solve for the y-intercept by plugging in the x and y values given from the coordinate into the equation with out new slope.

<h3 /><h3>Solve for B</h3>

$y = -\frac53x + b$
$-5 = -\frac53(15) + b$
$-5 = -25 + b$
$20 = b$

The y-intercept of the new line is 20.

The equation is $y = -\frac53x + 20$

6 0

2 years ago

What decimal is equivalent to 7/8

aleksley [76]

7/8 = 0.875 is the decimal equivalent.

7 0

2 years ago

Read 2 more answers

Fifteen telephones have just been received at an authorized service center. Five of these telephones are cellular, five are cord

viktelen [127]

Answer:

a) The probability of getting all (ﬁve) cordless phones among the ﬁrst 10 is 0.0839.

b) The probability of having exactly two types in the last five is 0.24975.

c) To pick a sample of size 6 which contains two of each type of phone. The probability of selecting 2 phones from each type is 0.199800.

Step-by-step explanation:

a) The ﬁrst ten serviced (without regard to order within the ﬁrst ten) constitute a random sample without replacement of size 10 from 15 phones.

So, such samples are: (Using Combination "C")

(15C10) $=3003\\$

We now regard the phones as of just two types: cordless or not-cordless. The not-cordless phones are the cellular and regular phones, and there are 10 such phones.

So, The number of ways to pick 5 cordless and 5 non-cordless is

(5C5) $*\\$ (10C5) $=252$

Thus the probability of getting all (ﬁve) cordless phones among the ﬁrst 10 is

$\frac{252}{3003} =0.0839$

b) Regard the last 5 phones (without regard to order within the last 5) as a sample with replacement from the 15 phones.There are (15C5) such samples.

Thus

There are (3C2)= 3 ways to choose the two types. For each such choice there are (10C5)= 252 possible ways to get a sample of size 5 from only these two types of phones.

also as the 2 of these samples contain all phones of same type so,

252-2 = 250

250 ways are to pick from these two types, having both type restricted.

then the probability will be

$\frac{3*(250)}{15C5} =0.249756$

c) We want to the ﬁnd the probability that two phones of each type are among the ﬁrst six serviced. The ﬁrst six serviced can be regarded, when ignoring the order among the ﬁrst 6, as an unordered sample of size 6 from 15 objects. so, there are (15C6) samples.

And there are $(15C2)^3$ ways to pick from each 3 types of phones.