Amplitude:
we can see that
maximum value is 3
minimum value is -1
so,



Period:
It is time completed after which value repeats itself
so, we get


so,
option-D............Answer
This equation may be illustrating Symmetric Property of Equality
Answer:
16.65
Step-by-step explanation:
15 percent of 111 is the same as 15 per hundred of 111. We can therefore make the following equation:
15/100 = X/111
To solve the equation above for X, you first switch the sides to get the X on the left side, then you multiply each side by 111, and then finally divide the numerator by the denominator on the right side to get the answer. Here is the work to illustrate:
15/100 = X/111
X/111 = 15/100
X*111/111 = 15*111/100
X = 1665/100
X = 16.65
or
The work above shows the long way to explain how to calculate 15 percent of 111 in order to give you a foundation and better understanding of how to calculate percentage. In the future, you could use this simplified formula:
(Y * P)/100
In our problem "What is 15 percent of 111?", Y is 111 and P is 15:
(111 * 15)/100 = 16.65
And once again you see that the answer is 16.65.
Answer:
(-x,-y)
180*
Step-by-step explanation:
This is the right answer
There are 4 teams in total and each team has 7 members. One of the team will be the host team.
Tournament committee will be made from 3 members from the host team and 2 members from each of the three remaining teams. Selecting the members for tournament committee is a combinations problem. We have to select 3 members out 7 for host team and 2 members out of 7 from each of the remaining 3 teams.
So total number of possible 9 member tournament committees will be equal to:

This is the case when a host team is fixed. Since any team can be the host team, there are 4 possible ways to select a host team. So the total number of possible 9 member tournament committee will be:

Therefore, there are 2917215 possible 9 member tournament committees